uva507 - Jill Rides Again(最长连续和)
2014-07-17 15:02
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题目:uva507 - Jill Rides Again(最长连续和)
题目大意:给每两个站之间的满意度,满意的路线必须加起来的和不小于0.帮Jill找出她满意的路线,要求是最长的,并且一样长的话取站相对靠前的。
代码:
题目大意:给每两个站之间的满意度,满意的路线必须加起来的和不小于0.帮Jill找出她满意的路线,要求是最长的,并且一样长的话取站相对靠前的。
代码:
#include <stdio.h> #include <string.h> const int N = 20005; int s, b, e; int stop ; int solve () { int mm = stop[1]; int sum = stop[1]; int tems = 1; b = e = 1; if (sum < 0) { tems = 2; sum = 0; } for (int i = 2; i < s; i++) { sum += stop[i]; if (sum < 0) { tems = i + 1; sum = 0; } else if (sum >= mm) { if ( (sum == mm && i - tems > e - b) || sum > mm) { b = tems; e = i; mm = sum; } } } return mm; } int main () { int t; scanf ("%d", &t); for (int i = 1; i <= t; i++) { scanf("%d", &s); for (int j = 1; j < s; j++) scanf ("%d", &stop[j]); int mm = solve(); if (mm < 0) printf ("Route %d has no nice parts\n", i); else printf ("The nicest part of route %d is between stops %d and %d\n", i, b, e + 1); } return 0; }
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