Drainage Ditches

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题意：有一个池塘因为下雨，通过修通渠道来排水，怎么排的水最多？

解析：经典最大流，通过改变容量，来减少流量的使用，实现了空间优化

#include<iostream>
#include<cmath>
#include<cstring>
#include<cstdio>
#include<queue>

using namespace std;

const int maxn = 1005;
#define INF 0xfffffff
int n, m, u, v, value, sum, start, end;
int pre[ maxn ], cap[ maxn ][ maxn ], flow[ maxn ][ maxn ], dis[ maxn ];

int EK (){

queue< int > Q;
sum = 0;
while( 1 ){
Q.push( start );
memset( dis, 0, sizeof( dis ) );
dis[ start ] = INF;
while( !Q.empty() ){
int temp = Q.front();
Q.pop();
for( int i = 1; i <= m; ++i ){
if( ! dis[ i ] && cap[ temp ][ i ] > 0 ){
dis[ i ] = min( dis[ temp ], cap[ temp ][ i ] );
pre[ i ] = temp;
Q.push( i );
}
}
}
if( dis[ m ] == 0 )
break;
sum += dis[ m ];
for( int i = end; i != start; i = pre[ i ] ){
cap[ pre[ i ] ][ i ] -= dis[ m ];
cap[ i ][ pre[ i ] ] += dis[ m ];
}
}
printf( "%d\n", sum );
}

int main(){
while( scanf( "%d%d", &n, &m ) != EOF ){
memset( cap, 0, sizeof( cap ) );
memset( flow, 0, sizeof( flow ) );
start = 1, end = m;
for( int i = 0; i < n; ++i ){
scanf( "%d%d%d", &u, &v, &value );
cap[ u ][ v ] += value;
}
EK( );
}
}

/*
5 4
1 2 40
1 4 20
2 4 20
2 3 30
3 4 10

50
*/