5 Binary String Matching

Binary String Matching

时间限制：3000 ms | 内存限制：65535 KB
难度：3

描述Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110110’ while the pattern string A is
‘11’, you should output 3, because the pattern A appeared at the posit

输入The first line consist only one integer N, indicates N cases follows. In each case, there are two lines, the first line gives the string A, length (A) <= 10, and the second line gives the string B, length (B) <= 1000. And
it is guaranteed that B is always longer than A.
输出For each case, output a single line consist a single integer, tells how many times do B appears as a substring of A.
样例输入

3
11
1001110110
101
110010010010001
1010
110100010101011

样例输出

3
0
3

#include<iostream>
#include<stdio.h>
#include<cstring>
using namespace std;

int main()
{
int n,m;
char a[11],b[1001],*s;
scanf("%d",&n);
while(n--)
{
m=0;
scanf("%s%s",&a,&b);
s=strstr(b,a);
while(s!=NULL)
{
m++;
strcpy(b,s);
b[0]=a[0]+1;
s=strstr(b,a);
}
printf("%d\n",m);
}
}