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2014-07-07 20:08 477 查看

John

Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)

Total Submission(s): 2659    Accepted Submission(s): 1462


[align=left]Problem Description[/align]
Little John is playing very funny game with his younger brother. There is one big box filled with M&Ms of different colors. At first John has to eat several M&Ms of the same color. Then his opponent has to make a turn. And so on.
Please note that each player has to eat at least one M&M during his turn. If John (or his brother) will eat the last M&M from the box he will be considered as a looser and he will have to buy a new candy box.

Both of players are using optimal game strategy. John starts first always. You will be given information about M&Ms and your task is to determine a winner of such a beautiful game.

 

[align=left]Input[/align]
The first line of input will contain a single integer T – the number of test cases. Next T pairs of lines will describe tests in a following format. The first line of each test will contain an integer N – the amount of different M&M
colors in a box. Next line will contain N integers Ai, separated by spaces – amount of M&Ms of i-th color.

Constraints:

1 <= T <= 474,

1 <= N <= 47,

1 <= Ai <= 4747

 

[align=left]Output[/align]
Output T lines each of them containing information about game winner. Print “John” if John will win the game or “Brother” in other case.

 

[align=left]Sample Input[/align]

2
3
3 5 1
1
1

规定吃完最后一颗的就输了,anti_sg,我也不是很懂,就是当所有堆都是1的时候特判,然后有一堆大于1的时候就按照nim游戏来做

博弈实在弱爆了!被博弈各种爆菊!

#include<cstdio>
#include<vector>
#include<utility>
#include<cstring>
#include<iostream>
#include<algorithm>
#define LL long long
#define MM 100010
using namespace std;

int n;
int main() {
int T;
//freopen("D:\\o.txt", "r", stdin);
scanf("%d", &T);
while (T--)
{
int sum = 0, num = 0;
scanf("%d", &n);
for (int i = 1; i <= n; i++)
{
int x;
scanf("%d", &x);
if (x > 1)num++;
sum ^= x;
}
if (num == 0)
{
if (n % 2 == 1)puts("Brother");
else puts("John");
}
else
{
if (sum != 0)puts("John");
else puts("Brother");
}
}
return 0;
}
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标签:  博弈 nim