hdu 1847(博弈)
2014-06-28 20:03
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/* hdu 1847(博弈) Kiki的必败态:(n%3==0); */ #include<iostream> #include<cstdio> using namespace std; int main() { int n; while(scanf("%d",&n)==1) { if(n%3==0) { printf("Cici\n"); } else { printf("Kiki\n"); } } return 0; }
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