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LeetCode——Sum Root to Leaf Numbers

2014-06-26 19:23 381 查看
Given a binary tree containing digits from 
0-9
 only, each root-to-leaf
path could represent a number.

An example is the root-to-leaf path 
1->2->3
 which represents the number 
123
.

Find the total sum of all root-to-leaf numbers.

For example,
1
/ \
2   3


The root-to-leaf path 
1->2
 represents the number 
12
.

The root-to-leaf path 
1->3
 represents the number 
13
.

Return the sum = 12 + 13 = 
25
.

给定一个仅包含0-9数字的二叉树,每个根到叶的路径可以代表一个数。

一个例子 根到叶的路径 
1->2->3
 代表数123.

找出所有根到叶 数的和。

想到就是深度优先遍历。

public int sumNumbers(TreeNode root) {
return dfs(root, 0);
}

public int dfs(TreeNode root, int sum) {
if (root == null)
return 0;
sum = sum * 10 + root.val;
if (root.left == null && root.right == null)
return sum;
return dfs(root.left, sum) + dfs(root.right, sum);
}
// Definition for binary tree
public class TreeNode {
int val;
TreeNode left;
TreeNode right;
TreeNode(int x) {
val = x;
}
}
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标签:  leetcode