linux系统下的获取系统时间并转为年月日格式

#include<time.h>

#include<stdio.h>

int main(void)

{

struct tm * timenow;

time_t second=time(0);

timenow=localtime(&second);

char timechar[256]={0};

sprinf(timechar,"%d-%d-%d %d:%d:%d",timenow->tm_year+1900,timenow->tm_mon+1,timenow->tm_mday,timenow->tm_hour,timenow->tm_min,timenow->tm_sec);

printf("%s",timechar);

}