UVa 10209 - Is This Integration ?
2014-06-24 10:17
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题目:一个边长为a的正方形,以每个顶点为圆心a为半径作圆,问形成的3种图形的面积。
分析:计算几何。根据题意立方程求解。设中心为x,等边三角形类似物为y,剩下的为z。
1.四分之一圆的面积:x + 3y + 2z = 0.25a^2
2.整体正方体的面积:x + 4y + 4z = a^2
3.两部分圆覆盖面积:x + 2y + z = (pi/3 - sqrt(3)/4)a^2
说明:UVa终于进入前1500了,CSDN也进入前2000了,(*^__^*)
分析:计算几何。根据题意立方程求解。设中心为x,等边三角形类似物为y,剩下的为z。
1.四分之一圆的面积:x + 3y + 2z = 0.25a^2
2.整体正方体的面积:x + 4y + 4z = a^2
3.两部分圆覆盖面积:x + 2y + z = (pi/3 - sqrt(3)/4)a^2
说明:UVa终于进入前1500了,CSDN也进入前2000了,(*^__^*)
#include <iostream> #include <cstdlib> #include <cstdio> #include <cmath> #define PI acos(-1.0) int main() { double a,x,y,z; while( ~scanf("%lf",&a) ) { z = a*a * (1.0 - PI/6.0 - 0.25*sqrt(3.0)); y = a*a - 0.25*PI*a*a - 2.0*z; x = a*a - 4*y - 4*z; printf("%.3lf %.3lf %.3lf\n",x,4.0*y,4.0*z); } return 0; }
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