[C/C++]使用上下左右控制菜单项

实现功能：

使用上下键切换菜单项

使用左右键返回或进入

使用Esc键退出菜单

编译通过：VS2013

代码如下：

#include <iostream>
using std::cout;
using std::endl;
#include <string>
using std::string;
#include <conio.h>
#include <windows.h>

#define MI 3//menu iterm number

void gotoxy(int x, int y)
{
COORD coord;
coord.X = x;coord.Y = y;
SetConsoleCursorPosition(GetStdHandle(STD_OUTPUT_HANDLE), coord);
}

int main(void)
{

int fr = 0;//sign to row
int fc = 0;//sign to column
int g;//gets the keyboard value

string bars = "\n\n\t\t------------------------------------------------\n"
"\t\t|***-------------- Menu Bar --------------***|\n"
"\t\t------------------------------------------------\n";
string menu[MI] = { "menu1", "menu2", "menu3" };
string pich = "\t\t\t\t ->\t";
loop:
system("cls");
cout << bars;
do {
gotoxy(0, 6);
for (int index = 0; index < MI; ++index)
{
if (fr == index)
{
cout << pich;
cout << menu[index] << endl;
}
else
cout << "\t\t\t\t\t" << menu[index] << endl;
if (fc != 0)
{
system("cls");
cout << bars;
if (fc == 1)
{
if (fr == 0)
cout << "\t\t\t\tenter " << menu[0];
else if (fr == 1)
cout << "\t\t\t\tenter " << menu[1];
else if (fr == 2)
cout << "\t\t\t\tenter " << menu[2];
}
else if (fc == -1)
cout << "\t\t\tReturn to the previous menu!";
cout << "\n\t\t\t\t";
system("pause");
fc = 0;
goto loop;
}
}
g = _getch();
switch (g)
{
case 0x48: //up
--fr;
if (fr < 0)
fr = MI - 1;
break;
case 0x50: //down
++fr;
if (fr > MI - 1)
fr = 0;
break;
case 0x4b: //left
fc = -1;
break;
case 0x4d: //right
fc = 1;
break;
}
} while (g != 0x1b); //Esc to quit

return 0;
}