LeetCode 57 Length of Last Word
2014-06-18 14:37
525 查看
Given a string s consists of upper/lower-case alphabets and empty space characters
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s =
return
' ', return the length of last word in the string.
If the last word does not exist, return 0.
Note: A word is defined as a character sequence consists of non-space characters only.
For example,
Given s =
"Hello World",
return
5.
public class Solution { public int lengthOfLastWord(String s) { String [] temp=s.split(" "); if(temp.length==0) return 0; if(temp[temp.length-1].isEmpty()) return 0; return temp[temp.length-1].length(); } }
相关文章推荐
- LeetCode(57)LengthOfLastWord
- LeetCode Online Judge 题目C# 练习 - Length of Last Word
- [LeetCode] Length of Last Word
- leetcode Length of Last Word
- LeetCode | Length of Last Word
- LeetCode_Length Of Last Word
- 【LeetCode with Python】 Length of Last Word
- [leetcode]Length of Last Word
- LeetCode - Length of Last Word
- leetcode: Length of Last Word
- LeetCode_Length of Last Word
- LeetCode Length of Last Word
- leetcode 21: Length of Last Word
- leetcode 21: Length of Last Word
- leetcode:Length of Last Word
- [Leetcode 3] 58 Length of Last Word
- LeetCode: Length of Last Word
- [LeetCode] Length of Last Word
- [leetcode]Length of Last Word
- [leetcode]Length of Last Word