简单枚举类型——植物与颜色 （SDUT 1959）


简单枚举类型——植物与颜色

Time Limit: 1000MS Memory limit: 65536K

题目描述

请定义具有red, orange, yellow, green, blue, violet六种颜色的枚举类型color，根据输入的颜色名称，输出以下六种植物花朵的颜色：
Rose(red), Poppies(orange), Sunflower(yellow), Grass(green), Bluebells(blue), Violets(violet)。如果输入的颜色名称不在枚举类型color中，例如输入purple，请输出I don't know about the color purple.

输入

输入数据有多行，每行有一个字符串代表颜色名称，颜色名称最多30个字符，直到文件结束为止。

输出

输出对应颜色的植物名称，例如：Bluebells are yellow. 如果输入的颜色名称不在枚举类型color中，例如purple, 请输出I don't know about the color purple.

示例输入

blue
yellow
purple

示例输出

Bluebells are blue.
Sunflower are yellow.
I don't know about the color purple.

提示

请用枚举类型实现。

来源

lxh

示例程序

#include <stdio.h>
#include <string.h>
int main()
{
char str[20];
enum color{red,orange,yellow,green,blue,violet};
while (gets(str)!=NULL)
{
if(strcmp(str,"red")==0)
printf("Rose are red.\n");
else if(strcmp(str,"orange")==0)
printf("Poppies are orange.\n");
else if(strcmp(str,"yellow")==0)
printf("Sunflower are yellow.\n");
else if(strcmp(str,"green")==0)
printf("Grass are green.\n");
else if(strcmp(str,"blue")==0)
printf("Bluebells are blue.\n");
else if(strcmp(str,"violet")==0)
printf("Violets are violet.\n");
else
printf("I don't know about the color %s.\n",str);

}
return 0;
}