LeetCode 26. Remove Duplicates from Sorted Array
2014-06-17 02:23
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和LeetCode 25. Remove Element差不多个意思。
数组去重,剩下的元素排在前面,返回数组长度。
代码:
class Solution
{
public:
int removeDuplicates(int A[], int n)
{
int ret = 0;
for (int i = 0; i < n; ++ i)
{
if (i!=0 && A[i]==A[i-1])
{
continue;
} else
{
A[ret ++] = A[i];
}
}
return ret;
}
};
数组去重,剩下的元素排在前面,返回数组长度。
代码:
class Solution
{
public:
int removeDuplicates(int A[], int n)
{
int ret = 0;
for (int i = 0; i < n; ++ i)
{
if (i!=0 && A[i]==A[i-1])
{
continue;
} else
{
A[ret ++] = A[i];
}
}
return ret;
}
};
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