UIMenuController IOS 弹出菜单

1. 创建并初始化  弹出菜单

    UIMenuController *menuController = [UIMenuController sharedMenuController];

    

    //@selector()括号中为该按钮触发的方法，该方法必须在UIVIewContrller中进行声明，就是投向的view所绑定的viewController类中必须实现这个方法

    UIMenuItem *menuItem_1 = [[UIMenuItem alloc] initWithTitle:@"复制" action:@selector(test1)];

    UIMenuItem *menuItem_2 = [[UIMenuItem alloc] initWithTitle:@"删除" action:@selector(test2)];

    UIMenuItem *menuItem_3 = [[UIMenuItem alloc] initWithTitle:@"移动" action:@selector(test3)];

    menuController.menuItems = [NSArray arrayWithObjects: menuItem_1, menuItem_2,menuItem_3,nil];

    

    [menuController setTargetRect:CGRectMake(100, 200, 60, 60) inView:self.view];

    [menuController setMenuVisible:YES animated:YES];

2. 添加  弹出菜单  的view要实现如下方法

- (BOOL)canBecomeFirstResponder
{

    return
YES;
}