leetcode:Sqrt(x)
2014-06-15 23:35
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public class Solution {
public int sqrt(int x) {
double ans = x;
while(Math.abs(ans * ans - x) > 0.0001)
{
ans = (ans + x / ans) / 2;
}
return (int)ans;
}
}
public int sqrt(int x) {
double ans = x;
while(Math.abs(ans * ans - x) > 0.0001)
{
ans = (ans + x / ans) / 2;
}
return (int)ans;
}
}
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