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Regular Expression Matching

2014-06-11 11:22 162 查看
class Solution {

public:
bool isMatch(const char *s, const char *p) {

return match(s, 0, p, 0, 0);

}

bool match(const char*s, int i, const char* p, int j, char lastChar){

if(i>=strlen(s) && j>=strlen(p))
return true;

if(lastChar!=0){

if(i>strlen(s)) //no need go deeper
return false;
bool b1 = match(s, i, p, j, 0);
bool b2 = 0;
if(lastChar == s[i] || lastChar=='.'){
b2 = match(s, i+1, p, j, lastChar);
}
return b1||b2;

}

if(j+1<strlen(p) && p[j+1]=='*'){

char c = p[j];
j+=2;
while(j<strlen(p) && p[j]==c && j+1<strlen(p) && p[j+1]=='*') //a*a*a*a*
j+=2;
return match(s, i, p, j, c);
}

if(j>=strlen(p) || i>=strlen(s)) //after check c*
return false;

if(s[i] == p[j] || p[j]=='.')
return match(s, i+1, p, j+1, lastChar);
else
return false;

}
};


Implement regular expression matching with support for
'.'
and
'*'
.
'.' Matches any single character.
'*' Matches zero or more of the preceding element.

The matching should cover the entire input string (not partial).

The function prototype should be:
bool isMatch(const char *s, const char *p)

Some examples:
isMatch("aa","a") → false
isMatch("aa","aa") → true
isMatch("aaa","aa") → false
isMatch("aa", "a*") → true
isMatch("aa", ".*") → true
isMatch("ab", ".*") → true
isMatch("aab", "c*a*b") → true
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