LeetCodeOJ--Reverse Words in a String(python版本)
2014-06-09 11:09
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Given an input string, reverse the string word by word.
For example,
Given s = "
return "
click to show clarification.
Clarification:
What constitutes a word?
A sequence of non-space characters constitutes a word.
Could the input string contain leading or trailing spaces?
Yes. However, your reversed string should not contain leading or trailing spaces.
How about multiple spaces between two words?
Reduce them to a single space in the reversed string.
1.测试版本代码:
2.测试版本截图:
3.提交AC版本代码:
For example,
Given s = "
the sky is blue",
return "
blue is sky the".
click to show clarification.
Clarification:
What constitutes a word?
A sequence of non-space characters constitutes a word.
Could the input string contain leading or trailing spaces?
Yes. However, your reversed string should not contain leading or trailing spaces.
How about multiple spaces between two words?
Reduce them to a single space in the reversed string.
1.测试版本代码:
# -*- coding: cp936 -*- s = " tian zhai xing " print "Before s:",s def reverseWords(s): L = s.split() #单词拆分成列表 print "字符串以单词分割成列表: %s" % L L.reverse()#反转列表中单词 print "反转列表中的单词: %s" % L s1 = ' '.join(L)#列表以空格分割单词,返回字符串 print "以空格分隔列表中反转后的单词: %s" % s1 return s1 #return s1.rstrip()#字符串删除首尾空格和回车 L = reverseWords(s) print "Afer L :",L
2.测试版本截图:
3.提交AC版本代码:
class Solution: # @param s, a string # @return a string def reverseWords(self, s): L = s.split()#字符串以单词分隔成列表 L.reverse()#反转列表中的单词 s1 = ' '.join(L)#以空格分隔列表中反转后的单词,返回字符串 return s1
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