All in All(poj 1936)

All in All

Time Limit: 1000MS		Memory Limit: 30000K
Total Submissions: 27329		Accepted: 11176

DescriptionYou have devised a new encryption technique which encodes a message by inserting between its characters randomly generated strings in a clever way. Because of pending patent issues we will not discuss in detail how the stringsare generated and inserted into the original message. To validate your method, however, it is necessary to write a program that checks if the message is really encoded in the final string.Given two strings s and t, you have to decide whether s is a subsequence of t, i.e. if you can remove characters from t such that the concatenation of the remaining characters is s.InputThe input contains several testcases. Each is specified by two strings s, t of alphanumeric ASCII characters separated by whitespace.The length of s and t will no more than 100000.OutputFor each test case output "Yes", if s is a subsequence of t,otherwise output "No".Sample Input

sequence subsequence
person compression
VERDI vivaVittorioEmanueleReDiItalia
caseDoesMatter CaseDoesMatter

Sample Output

Yes
No
Yes

No

Source

Ulm Local 2002

水题一枚~大体意思是要前一个字符串是后一个字符串的子串。注意是多组输入~

#include <stdio.h>#include <string.h>char str1[100010],str2[100010];int main(){int i,j,len1,len2;while (~scanf("%s %s",str1,str2)){len1=strlen(str1);len2=strlen(str2);if(len1>len2){printf("No\n");continue;}for(i=0,j=0;str1[i]!='\0'&&str2[j]!='\0';j++){if(str1[i]==str2[j])i++;}if(i==len1)printf("Yes\n");elseprintf("No\n");}return 0;}