OCP 1Z0 052 3
2014-06-05 16:07
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3. While observing the index statistics, you find that an index is highly fragmented, thereby resulting in
poor database performance. Which option would you use to reduce fragmentation without affecting the
users who are currently using the index?
A.Validate the index structure using the ANALYZE...INDEX command.
B.Rebuild the index using the ALTER INDEX..REBUILD ONLINE command.
C.Change the block space utilization parameters using the ALTER INDEX command.
D.Deallocate the unused space in the index using the ALTER INDEX..DEALLOCATE UNUSED command.
Answer: B
A anylyze 是分析,不能减少碎片
B 重建索引如果不加online会要求表级锁
poor database performance. Which option would you use to reduce fragmentation without affecting the
users who are currently using the index?
A.Validate the index structure using the ANALYZE...INDEX command.
B.Rebuild the index using the ALTER INDEX..REBUILD ONLINE command.
C.Change the block space utilization parameters using the ALTER INDEX command.
D.Deallocate the unused space in the index using the ALTER INDEX..DEALLOCATE UNUSED command.
Answer: B
A anylyze 是分析,不能减少碎片
B 重建索引如果不加online会要求表级锁
SQL> DROP TABLE TEST 2 / Table dropped Executed in 0.047 seconds SQL> CREATE TABLE TEST AS SELECT * FROM Dba_Objects 2 / Table created Executed in 1.829 seconds SQL> DECLARE 2 v_date DATE := SYSDATE + 6 / 24 / 60 / 60; 3 v_seconds INT; 4 BEGIN 5 dbms_scheduler.create_job(job_name => 'TEST_JOB', 6 job_type => 'PLSQL_BLOCK', 7 job_action => 'DECLARE 8 V_DATE DATE := SYSDATE + 10 / 24 / 60 / 60; 9 BEGIN 10 UPDATE TEST SET created = created + 1 where rownum <= 1; 11 LOOP 12 EXIT WHEN SYSDATE >= V_DATE; 13 END LOOP; 14 COMMIT; 15 END;', 16 start_date => SYSDATE, 17 enabled => TRUE, 18 auto_drop => TRUE); 19 20 LOOP 21 SELECT max(extract(SECOND FROM elapsed_time)) 22 INTO v_seconds 23 FROM dba_scheduler_running_jobs 24 WHERE job_name = upper('TEST_JOB'); 25 EXIT WHEN SYSDATE >= v_date OR v_seconds >= 2; 26 END LOOP; 27 END; 28 / PL/SQL procedure successfully completed Executed in 1.547 seconds SQL> SELECT job_name 2 FROM dba_scheduler_running_jobs 3 WHERE job_name = upper('TEST_JOB') 4 / JOB_NAME ------------------------------ TEST_JOB 1 row selected Executed in 0.016 seconds SQL> create index idx_test on test(object_id) 2 / create index idx_test on test(object_id) ORA-00054: resource busy and acquire with NOWAIT specified or timeout expired
SQL> DECLARE 2 v_date DATE := SYSDATE + 6 / 24 / 60 / 60; 3 v_seconds INT; 4 BEGIN 5 dbms_scheduler.create_job(job_name => 'TEST_JOB', 6 job_type => 'PLSQL_BLOCK', 7 job_action => 'DECLARE 8 V_DATE DATE := SYSDATE + 10 / 24 / 60 / 60; 9 BEGIN 10 UPDATE TEST SET created = created + 1 where rownum <= 1; 11 LOOP 12 EXIT WHEN SYSDATE >= V_DATE; 13 END LOOP; 14 COMMIT; 15 END;', 16 start_date => SYSDATE, 17 enabled => TRUE, 18 auto_drop => TRUE); 19 20 LOOP 21 SELECT max(extract(SECOND FROM elapsed_time)) 22 INTO v_seconds 23 FROM dba_scheduler_running_jobs 24 WHERE job_name = upper('TEST_JOB'); 25 EXIT WHEN SYSDATE >= v_date OR v_seconds >= 2; 26 END LOOP; 27 END; 28 / PL/SQL procedure successfully completed Executed in 1.532 seconds SQL> SELECT job_name 2 FROM dba_scheduler_running_jobs 3 WHERE job_name = upper('TEST_JOB') 4 / JOB_NAME ------------------------------ TEST_JOB 1 row selected Executed in 0.031 seconds SQL> create index idx_test on test(object_id) online 2 / Index created Executed in 8.078 seconds
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