解惑 getHibernateSession().createCriteria(*).add(Restrictions.in(*)).list()
2014-06-04 16:22
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前言:才知道,Hibernate中共提供了三种检索方式:HQL(Hibernate Query Language)、QBC(Query By Criteria)、QBE(Query By Example)。而今天的这个查询方法属于QBC,牢记牢记。
以下内容摘自:http://blog.csdn.net/yongqingmiao/article/details/7717745
List list=getHibernateSession().createCriteria(MeterUser.class).add(Restrictions.eq("name", "11")).addOrder(Order.desc("userid")).list();
Restrictions的用法:
QBC常用限定方法
Restrictions.eq --> equal,等于.
Restrictions.allEq --> 参数为Map对象,使用key/value进行多个等于的比对,相当于多个Restrictions.eq的效果
Restrictions.gt --> great-than > 大于
Restrictions.ge --> great-equal >= 大于等于
Restrictions.lt --> less-than, < 小于
Restrictions.le --> less-equal <= 小于等于
Restrictions.between --> 对应SQL的between子句
Restrictions.like --> 对应SQL的LIKE子句
Restrictions.in --> 对应SQL的in子句
Restrictions.and --> and 关系
Restrictions.or --> or 关系
Restrictions.isNull --> 判断属性是否为空,为空则返回true
Restrictions.isNotNull --> 与isNull相反
Restrictions.sqlRestriction --> SQL限定的查询
Order.asc --> 根据传入的字段进行升序排序
Order.desc --> 根据传入的字段进行降序排序
MatchMode.EXACT --> 字符串精确匹配.相当于"like 'value'"
MatchMode.ANYWHERE --> 字符串在中间匹配.相当于"like '%value%'"
MatchMode.START --> 字符串在最前面的位置.相当于"like 'value%'"
MatchMode.END --> 字符串在最后面的位置.相当于"like '%value'"
例子
查询年龄在20-30岁之间的所有学生对象
List list = session.createCriteria(Student.class)
.add(Restrictions.between("age",new Integer(20),new Integer(30)).list();
查询学生姓名在AAA,BBB,CCC之间的学生对象
String[] names = {"AAA","BBB","CCC"};
List list = session.createCriteria(Student.class)
.add(Restrictions.in("name",names)).list();
查询年龄为空的学生对象
List list = session.createCriteria(Student.class)
.add(Restrictions.isNull("age")).list();
查询年龄等于20或者年龄为空的学生对象
List list = session.createCriteria(Student.class)
.add(Restrictions.or(Restrictions.eq("age",new Integer(20)),
Restrictions.isNull("age")).list();
--------------------------------------------------------------------
使用QBC实现动态查询
public List findStudents(String name,int age){
Criteria criteria = session.createCriteria(Student.class);
if(name != null){
criteria.add(Restrictions.like("name",name,MatchMode.ANYWHERE));
}
if(age != 0){
criteria.add(Restrictions.eq("age",new Integer(age)));
}
criteria.addOrder(Order.asc("name"));//根据名字升序排列
return criteria.list();
}
-----------------------------------------------------------------------------------
今天用了写hibernate高级查询时用了Restrictions(当然Expression也是可以以的)这个类.感觉不错.
下面的代码写的不易读.其实核心就是一句
Restrictions.or(Restrictions.like(),Restrictions.or(Restrictions.like,........))
里面的or可以无限加的.还是比较好用
Session session = getHibernateTemplate().getSessionFactory()
.openSession();
Criteria criteria = session.createCriteria(Film.class);
List<Film> list = criteria.add(
Restrictions.or(Restrictions.like("description", key,MatchMode.ANYWHERE),
Restrictions.or(Restrictions.like("name", key,MatchMode.ANYWHERE),
Restrictions.or( Restrictions.like("direct", key,MatchMode.ANYWHERE),
Restrictions.or(Restrictions.like("mainplay",key,MatchMode.ANYWHERE),
Restrictions.like("filearea", key,MatchMode.ANYWHERE)))))).list();
session.close();
return list;
以下内容摘自:http://blog.csdn.net/yongqingmiao/article/details/7717745
List list=getHibernateSession().createCriteria(MeterUser.class).add(Restrictions.eq("name", "11")).addOrder(Order.desc("userid")).list();
Restrictions的用法:
QBC常用限定方法
Restrictions.eq --> equal,等于.
Restrictions.allEq --> 参数为Map对象,使用key/value进行多个等于的比对,相当于多个Restrictions.eq的效果
Restrictions.gt --> great-than > 大于
Restrictions.ge --> great-equal >= 大于等于
Restrictions.lt --> less-than, < 小于
Restrictions.le --> less-equal <= 小于等于
Restrictions.between --> 对应SQL的between子句
Restrictions.like --> 对应SQL的LIKE子句
Restrictions.in --> 对应SQL的in子句
Restrictions.and --> and 关系
Restrictions.or --> or 关系
Restrictions.isNull --> 判断属性是否为空,为空则返回true
Restrictions.isNotNull --> 与isNull相反
Restrictions.sqlRestriction --> SQL限定的查询
Order.asc --> 根据传入的字段进行升序排序
Order.desc --> 根据传入的字段进行降序排序
MatchMode.EXACT --> 字符串精确匹配.相当于"like 'value'"
MatchMode.ANYWHERE --> 字符串在中间匹配.相当于"like '%value%'"
MatchMode.START --> 字符串在最前面的位置.相当于"like 'value%'"
MatchMode.END --> 字符串在最后面的位置.相当于"like '%value'"
例子
查询年龄在20-30岁之间的所有学生对象
List list = session.createCriteria(Student.class)
.add(Restrictions.between("age",new Integer(20),new Integer(30)).list();
查询学生姓名在AAA,BBB,CCC之间的学生对象
String[] names = {"AAA","BBB","CCC"};
List list = session.createCriteria(Student.class)
.add(Restrictions.in("name",names)).list();
查询年龄为空的学生对象
List list = session.createCriteria(Student.class)
.add(Restrictions.isNull("age")).list();
查询年龄等于20或者年龄为空的学生对象
List list = session.createCriteria(Student.class)
.add(Restrictions.or(Restrictions.eq("age",new Integer(20)),
Restrictions.isNull("age")).list();
--------------------------------------------------------------------
使用QBC实现动态查询
public List findStudents(String name,int age){
Criteria criteria = session.createCriteria(Student.class);
if(name != null){
criteria.add(Restrictions.like("name",name,MatchMode.ANYWHERE));
}
if(age != 0){
criteria.add(Restrictions.eq("age",new Integer(age)));
}
criteria.addOrder(Order.asc("name"));//根据名字升序排列
return criteria.list();
}
-----------------------------------------------------------------------------------
今天用了写hibernate高级查询时用了Restrictions(当然Expression也是可以以的)这个类.感觉不错.
下面的代码写的不易读.其实核心就是一句
Restrictions.or(Restrictions.like(),Restrictions.or(Restrictions.like,........))
里面的or可以无限加的.还是比较好用
Session session = getHibernateTemplate().getSessionFactory()
.openSession();
Criteria criteria = session.createCriteria(Film.class);
List<Film> list = criteria.add(
Restrictions.or(Restrictions.like("description", key,MatchMode.ANYWHERE),
Restrictions.or(Restrictions.like("name", key,MatchMode.ANYWHERE),
Restrictions.or( Restrictions.like("direct", key,MatchMode.ANYWHERE),
Restrictions.or(Restrictions.like("mainplay",key,MatchMode.ANYWHERE),
Restrictions.like("filearea", key,MatchMode.ANYWHERE)))))).list();
session.close();
return list;
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