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解惑 getHibernateSession().createCriteria(*).add(Restrictions.in(*)).list()

2014-06-04 16:22 393 查看
前言:才知道,Hibernate中共提供了三种检索方式:HQL(Hibernate Query Language)、QBC(Query By Criteria)、QBE(Query By Example)。而今天的这个查询方法属于QBC,牢记牢记。

 

以下内容摘自:http://blog.csdn.net/yongqingmiao/article/details/7717745

  List list=getHibernateSession().createCriteria(MeterUser.class).add(Restrictions.eq("name", "11")).addOrder(Order.desc("userid")).list();

 

Restrictions的用法:

QBC常用限定方法

Restrictions.eq --> equal,等于.

Restrictions.allEq --> 参数为Map对象,使用key/value进行多个等于的比对,相当于多个Restrictions.eq的效果

Restrictions.gt --> great-than > 大于

Restrictions.ge --> great-equal >= 大于等于

Restrictions.lt --> less-than, < 小于

Restrictions.le --> less-equal <= 小于等于

Restrictions.between --> 对应SQL的between子句

Restrictions.like --> 对应SQL的LIKE子句

Restrictions.in --> 对应SQL的in子句

Restrictions.and --> and 关系

Restrictions.or --> or 关系

Restrictions.isNull --> 判断属性是否为空,为空则返回true

Restrictions.isNotNull --> 与isNull相反

Restrictions.sqlRestriction --> SQL限定的查询

Order.asc --> 根据传入的字段进行升序排序

Order.desc --> 根据传入的字段进行降序排序

MatchMode.EXACT --> 字符串精确匹配.相当于"like 'value'"

MatchMode.ANYWHERE --> 字符串在中间匹配.相当于"like '%value%'"

MatchMode.START --> 字符串在最前面的位置.相当于"like 'value%'"

MatchMode.END --> 字符串在最后面的位置.相当于"like '%value'"

例子

查询年龄在20-30岁之间的所有学生对象

List list = session.createCriteria(Student.class)

      .add(Restrictions.between("age",new Integer(20),new Integer(30)).list();

查询学生姓名在AAA,BBB,CCC之间的学生对象

String[] names = {"AAA","BBB","CCC"};

List list = session.createCriteria(Student.class)

      .add(Restrictions.in("name",names)).list();

查询年龄为空的学生对象

List list = session.createCriteria(Student.class)

      .add(Restrictions.isNull("age")).list();

查询年龄等于20或者年龄为空的学生对象

List list = session.createCriteria(Student.class)

      .add(Restrictions.or(Restrictions.eq("age",new Integer(20)),

                 Restrictions.isNull("age")).list();

--------------------------------------------------------------------
使用QBC实现动态查询

public List findStudents(String name,int age){

Criteria criteria = session.createCriteria(Student.class);

if(name != null){

  criteria.add(Restrictions.like("name",name,MatchMode.ANYWHERE));

}

if(age != 0){

  criteria.add(Restrictions.eq("age",new Integer(age)));

}

criteria.addOrder(Order.asc("name"));//根据名字升序排列

return criteria.list();

}

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今天用了写hibernate高级查询时用了Restrictions(当然Expression也是可以以的)这个类.感觉不错.

下面的代码写的不易读.其实核心就是一句

Restrictions.or(Restrictions.like(),Restrictions.or(Restrictions.like,........))

里面的or可以无限加的.还是比较好用

Session session = getHibernateTemplate().getSessionFactory()

                .openSession();

        Criteria criteria = session.createCriteria(Film.class);

        List<Film> list = criteria.add(

            Restrictions.or(Restrictions.like("description", key,MatchMode.ANYWHERE),

            Restrictions.or(Restrictions.like("name", key,MatchMode.ANYWHERE),

                Restrictions.or(    Restrictions.like("direct", key,MatchMode.ANYWHERE),

                Restrictions.or(Restrictions.like("mainplay",key,MatchMode.ANYWHERE),

                        Restrictions.like("filearea", key,MatchMode.ANYWHERE)))))).list();

        session.close();

        return list;
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