最小二乘曲线拟合——C语言算法实现一
2014-05-29 20:45
393 查看
最小二乘曲线拟合
![](http://img.blog.csdn.net/20140529200751609?watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvYmVpamluZ21ha2UyMDk=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/Center)
![](http://img.blog.csdn.net/20140529200925859?watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvYmVpamluZ21ha2UyMDk=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/Center)
![](http://img.blog.csdn.net/20140529201047406?watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvYmVpamluZ21ha2UyMDk=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/SouthEast)
![](http://img.blog.csdn.net/20140529201309343?watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvYmVpamluZ21ha2UyMDk=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/SouthEast)
![](http://img.blog.csdn.net/20140529201421468?watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvYmVpamluZ21ha2UyMDk=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/SouthEast)
![](http://img.blog.csdn.net/20140529201519921?watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvYmVpamluZ21ha2UyMDk=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/SouthEast)
![](http://img.blog.csdn.net/20140529201727656?watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvYmVpamluZ21ha2UyMDk=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/SouthEast)
![](http://img.blog.csdn.net/20140529203011796?watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvYmVpamluZ21ha2UyMDk=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/SouthEast)
![](http://img.blog.csdn.net/20140529203116015?watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvYmVpamluZ21ha2UyMDk=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/SouthEast)
![](http://img.blog.csdn.net/20140529203250312?watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvYmVpamluZ21ha2UyMDk=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/SouthEast)
![](http://img.blog.csdn.net/20140529203356812?watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvYmVpamluZ21ha2UyMDk=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/SouthEast)
![](http://img.blog.csdn.net/20140529203458140?watermark/2/text/aHR0cDovL2Jsb2cuY3Nkbi5uZXQvYmVpamluZ21ha2UyMDk=/font/5a6L5L2T/fontsize/400/fill/I0JBQkFCMA==/dissolve/70/gravity/SouthEast)
给定一组数据,我们要对这组数据进行曲线拟合。
假定要拟合的曲线方程为 y=a0 + a1*x^1 + a2*x^2 + a3*x^3 + ...+ an*x^n
x y
0.995119 -7.620000
2.001185 -2.460000
2.999068 108.760000
4.001035 625.020000
4.999859 2170.500000
6.004461 5814.580000
6.999335 13191.840000
7.999433 26622.060000
9.002257 49230.220000
10.003888 85066.500000
11.004076 139226.280000
12.001602 217970.140000
13.003390 328843.860000
14.001623 480798.420000
15.003034 684310.000000
16.002561 951499.980000
17.003010 1296254.940000
18.003897 1734346.660000
19.002563 2283552.120000
20.003530 2963773.500000
代码如下:
输出结果为:
Amount: 20
拟合系数为:
按升序排列
ParaK[0] = 0.999157
ParaK[1] = -1.450258
ParaK[2] = -0.529332
ParaK[3] = 0.236626
ParaK[4] = 6.725930
ParaK[5] = -18.544115
拟合时间为: 9.000000ms
Matlab代码:
其中test.txt文件为上面的x,y向量
Matlab拟合系数,降序排列:
para = 0.9992 -1.4503 -0.5293 0.2366 6.7259 -18.5441
Matlab拟合曲线结果图:
给定一组数据,我们要对这组数据进行曲线拟合。
假定要拟合的曲线方程为 y=a0 + a1*x^1 + a2*x^2 + a3*x^3 + ...+ an*x^n
x y
0.995119 -7.620000
2.001185 -2.460000
2.999068 108.760000
4.001035 625.020000
4.999859 2170.500000
6.004461 5814.580000
6.999335 13191.840000
7.999433 26622.060000
9.002257 49230.220000
10.003888 85066.500000
11.004076 139226.280000
12.001602 217970.140000
13.003390 328843.860000
14.001623 480798.420000
15.003034 684310.000000
16.002561 951499.980000
17.003010 1296254.940000
18.003897 1734346.660000
19.002563 2283552.120000
20.003530 2963773.500000
代码如下:
#include "stdio.h" #include "stdlib.h" #include "math.h" #include <time.h> #define ParaBuffer(Buffer,Row,Col) (*(Buffer + (Row) * (SizeSrc + 1) + (Col))) /*********************************************************************************** ***********************************************************************************/ static int GetXY(const char* FileName, double* X, double* Y, int* Amount) { FILE* File = fopen(FileName, "r"); if (!File) return -1; for (*Amount = 0; !feof(File); X++, Y++, (*Amount)++) if (2 != fscanf(File, (const char*)"%lf %lf", X, Y)) break; fclose(File); return 0; } /*********************************************************************************** ***********************************************************************************/ static int PrintPara(double* Para, int SizeSrc) { int i, j; for (i = 0; i < SizeSrc; i++) { for (j = 0; j <= SizeSrc; j++) printf("%10.6lf ", ParaBuffer(Para, i, j)); printf("\r\n"); } printf("\r\n"); return 0; } /*********************************************************************************** ***********************************************************************************/ static int ParalimitRow(double* Para, int SizeSrc, int Row) { int i; double Max, Min, Temp; for (Max = abs(ParaBuffer(Para, Row, 0)), Min = Max, i = SizeSrc; i; i--) { Temp = abs(ParaBuffer(Para, Row, i)); if (Max < Temp) Max = Temp; if (Min > Temp) Min = Temp; } Max = (Max + Min) * 0.000005; for (i = SizeSrc; i >= 0; i--) ParaBuffer(Para, Row, i) /= Max; return 0; } /*********************************************************************************** ***********************************************************************************/ static int Paralimit(double* Para, int SizeSrc) { int i; for (i = 0; i < SizeSrc; i++) if (ParalimitRow(Para, SizeSrc, i)) return -1; return 0; } /*********************************************************************************** ***********************************************************************************/ static int ParaPreDealA(double* Para, int SizeSrc, int Size) { int i, j; for (Size -= 1, i = 0; i < Size; i++) { for (j = 0; j < Size; j++) ParaBuffer(Para, i, j) = ParaBuffer(Para, i, j) * ParaBuffer(Para, Size, Size) - ParaBuffer(Para, Size, j) * ParaBuffer(Para, i, Size); ParaBuffer(Para, i, SizeSrc) = ParaBuffer(Para, i, SizeSrc) * ParaBuffer(Para, Size, Size) - ParaBuffer(Para, Size, SizeSrc) * ParaBuffer(Para, i, Size); ParaBuffer(Para, i, Size) = 0; ParalimitRow(Para, SizeSrc, i); } return 0; } /*********************************************************************************** ***********************************************************************************/ static int ParaDealA(double* Para, int SizeSrc) { int i; for (i = SizeSrc; i; i--) if (ParaPreDealA(Para, SizeSrc, i)) return -1; return 0; } /*********************************************************************************** ***********************************************************************************/ static int ParaPreDealB(double* Para, int SizeSrc, int OffSet) { int i, j; for (i = OffSet + 1; i < SizeSrc; i++) { for (j = OffSet + 1; j <= i; j++) ParaBuffer(Para, i, j) *= ParaBuffer(Para, OffSet, OffSet); ParaBuffer(Para, i, SizeSrc) = ParaBuffer(Para, i, SizeSrc) * ParaBuffer(Para, OffSet, OffSet) - ParaBuffer(Para, i, OffSet) * ParaBuffer(Para, OffSet, SizeSrc); ParaBuffer(Para, i, OffSet) = 0; ParalimitRow(Para, SizeSrc, i); } return 0; } /*********************************************************************************** ***********************************************************************************/ static int ParaDealB(double* Para, int SizeSrc) { int i; for (i = 0; i < SizeSrc; i++) if (ParaPreDealB(Para, SizeSrc, i)) return -1; for (i = 0; i < SizeSrc; i++) { if (ParaBuffer(Para, i, i)) { ParaBuffer(Para, i, SizeSrc) /= ParaBuffer(Para, i, i); ParaBuffer(Para, i, i) = 1.0; } } return 0; } /*********************************************************************************** ***********************************************************************************/ static int ParaDeal(double* Para, int SizeSrc) { PrintPara(Para, SizeSrc); Paralimit(Para, SizeSrc); PrintPara(Para, SizeSrc); if (ParaDealA(Para, SizeSrc)) return -1; PrintPara(Para, SizeSrc); if (ParaDealB(Para, SizeSrc)) return -1; return 0; } /*********************************************************************************** ***********************************************************************************/ static int GetParaBuffer(double* Para, const double* X, const double* Y, int Amount, int SizeSrc) { int i, j; for (i = 0; i < SizeSrc; i++) for (ParaBuffer(Para, 0, i) = 0, j = 0; j < Amount; j++) ParaBuffer(Para, 0, i) += pow(*(X + j), 2 * (SizeSrc - 1) - i); for (i = 1; i < SizeSrc; i++) for (ParaBuffer(Para, i, SizeSrc - 1) = 0, j = 0; j < Amount; j++) ParaBuffer(Para, i, SizeSrc - 1) += pow(*(X + j), SizeSrc - 1 - i); for (i = 0; i < SizeSrc; i++) for (ParaBuffer(Para, i, SizeSrc) = 0, j = 0; j < Amount; j++) ParaBuffer(Para, i, SizeSrc) += (*(Y + j)) * pow(*(X + j), SizeSrc - 1 - i); for (i = 1; i < SizeSrc; i++) for (j = 0; j < SizeSrc - 1; j++) ParaBuffer(Para, i, j) = ParaBuffer(Para, i - 1, j + 1); return 0; } //*********************************************************************************** //*********************************************************************************** int Cal(const double* BufferX, const double* BufferY, int Amount, int SizeSrc, double* ParaResK) { double* ParaK = (double*)malloc(SizeSrc * (SizeSrc + 1) * sizeof(double)); GetParaBuffer(ParaK, BufferX, BufferY, Amount, SizeSrc); ParaDeal(ParaK, SizeSrc); for (Amount = 0; Amount < SizeSrc; Amount++, ParaResK++) *ParaResK = ParaBuffer(ParaK, Amount, SizeSrc); free(ParaK); return 0; } /*********************************************************************************** ***********************************************************************************/ int main(int argc, char* argv[]) { int Amount; clock_t StartTime, FinishTime; // 声明两个时间变量 double DiffTime; StartTime = clock(); // 开始计时 double BufferX[1024], BufferY[1024], ParaK[6]; // 5次拟合, 一共6个系数(包含常数项) // 读入要拟合的数据 if (GetXY((const char*)"test.txt", (double*)BufferX, (double*)BufferY, &Amount)) return 0; printf("Amount: %d\n", Amount); Cal((const double*)BufferX, (const double*)BufferY, Amount, sizeof(ParaK) / sizeof(double), (double*)ParaK); printf("拟合系数为:\n"); printf("按升序排列\n"); for (Amount = 0; Amount < sizeof(ParaK) / sizeof(double); Amount++) printf("ParaK[%d] = %lf\r\n", Amount, ParaK[Amount]); FinishTime = clock(); // 结束计时 DiffTime = FinishTime - StartTime; //拟合时间 printf("拟合时间为: %lf\n", DiffTime); return 0; }
输出结果为:
Amount: 20
拟合系数为:
按升序排列
ParaK[0] = 0.999157
ParaK[1] = -1.450258
ParaK[2] = -0.529332
ParaK[3] = 0.236626
ParaK[4] = 6.725930
ParaK[5] = -18.544115
拟合时间为: 9.000000ms
Matlab代码:
其中test.txt文件为上面的x,y向量
load test.txt; x = test(:, 1)'; y = test(:, 2)'; para = polyfit(x, y, 5) figure, plot(x,y,'b.') hold on plot(x,y,'r-')
Matlab拟合系数,降序排列:
para = 0.9992 -1.4503 -0.5293 0.2366 6.7259 -18.5441
Matlab拟合曲线结果图:
相关文章推荐
- 最小二乘曲线拟合matlab实现
- 最小二乘曲线拟合算法的C++实现
- 最小二乘曲线拟合matlab实现
- 最小二乘椭圆拟合matlab代码实现
- 简单好用的最小二乘椭圆拟合算法---MATLAB实现
- 使用scipy实现最小二乘法,以及通过曲线对数据进行拟合(Python)
- 最小二乘曲线拟合——C语言算法实现二
- 一元二次曲线拟合的最小二乘python实现
- 最小二乘法 多项式曲线拟合 原理公式理解 Python 实现
- 基于移动最小二乘的图像变形和曲线拟合
- python最小二乘和神经网络拟合曲线比较
- 最小二乘曲线拟合的MATLAB仿真
- 曲线拟合-B样条曲线(BCB实现)
- 最小二乘法多项式曲线拟合原理与实现
- 最小二乘法多项式曲线拟合原理与实现
- 基于直接最小二乘的椭圆拟合(Direct Least Squares Fitting of Ellipses)
- 最小二乘法多项式曲线拟合原理与实现
- 最小二乘法曲线拟合 C语言实现
- VC中实现最小二乘法 直线拟合 Y=a0+a1X 以及 Y=aX
- 最小二乘法完成曲线拟合公式