codeforces 118A String Task(字符串水题)

A. String Task

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time limit per test
2 seconds

memory limit per test
256 megabytes

input
standard input

output
standard output

Petya started to attend programming lessons. On the first lesson his task was to write a simple program. The program was supposed to do the following: in the given string, consisting if uppercase and lowercase Latin letters, it:

deletes all the vowels,
inserts a character "." before each consonant,

replaces all uppercase consonants with corresponding lowercase ones.

Vowels are letters "A", "O", "Y", "E", "U", "I", and the rest are consonants. The program's input is exactly one string, it should return the output as a single string, resulting after the program's processing the initial string.

Help Petya cope with this easy task.

Input
The first line represents input string of Petya's program. This string only consists of uppercase and lowercase Latin letters and its length is from
1 to 100, inclusive.

Output
Print the resulting string. It is guaranteed that this string is not empty.

Sample test(s)

Input

tour

Output

.t.r

Input

Codeforces

Output

.c.d.f.r.c.s

Input

aBAcAba

Output

.b.c.b

水题，直接代码：
[code]#include <iostream>
#include<string.h>
using namespace std;
int main()
{
    int k,i,t;
    char c[101],s[101];
    while(cin>>c)
    {
        k=strlen(c);
        for(i=0,t=0;i<k;i++)
        {
            if(!(c[i]=='A'||c[i]=='a'||c[i]=='O'||c[i]=='o'||c[i]=='Y'||c[i]=='y'||c[i]=='U'||c[i]=='u'||c[i]=='I'||c[i]=='i'||c[i]=='E'||c[i]=='e'))
            s[t++]=c[i];
        }
        for(i=0;i<t;i++)
        {
            cout<<".";
            if(s[i]>='A'&&s[i]<='Z')
                cout<<char(s[i]+32);
            else
                cout<<s[i];
        }
        cout<<endl;
        memset(c,101,sizeof(c[0]));
    }
    return 0;
}

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