服务器: 消息 170，级别 15，状态 1，行 14解决方法

服务器: 消息 170，级别 15，状态 1，行 14

SELECT c.ThreeCantonNumber as areano,c.ThreeCantonName,(a.FirstCantonName+b.SecondCantonName+c.ThreeCantonName) as AreaName from(

SELECT a.FirstCantonNumber, 

  b.SecondCantonNumber, 

  c.ThreeCantonNumber, a.FirstCantonName, 

  b.SecondCantonName, 

  c.ThreeCantonName

FROM dbo.T_FirstCanton a LEFT OUTER JOIN

  dbo.T_SecondCanton b ON 

  a.FirstCantonNumber = b.FirstCantonNumber LEFT

  OUTER JOIN

  dbo.T_ThreeCanton c ON 

  b.SecondCantonNumber = c.SecondCantonNumber

)
服务器: 消息 170，级别 15，状态 1，行 14

第 14 行: ')' 附近有语法错误。

------解决方案--------------------------------------------------------

SELECT c.ThreeCantonNumber as areano,c.ThreeCantonName,(a.FirstCantonName+b.SecondCantonName+c.ThreeCantonName) as AreaName from(
SELECT a.FirstCantonNumber,
b.SecondCantonNumber,
c.ThreeCantonNumber, a.FirstCantonName,
b.SecondCantonName,
c.ThreeCantonName
FROM dbo.T_FirstCanton a LEFT OUTER JOIN
dbo.T_SecondCanton b ON
a.FirstCantonNumber = b.FirstCantonNumber LEFT
OUTER JOIN
dbo.T_ThreeCanton c ON
b.SecondCantonNumber = c.SecondCantonNumber
) t--加个别名

------解决方案--------------------------------------------------------

SELECT c.ThreeCantonNumber as areano,c.ThreeCantonName,(a.FirstCantonName+b.SecondCantonName+c.ThreeCantonName) as AreaName from(
SELECT a.FirstCantonNumber,
b.SecondCantonNumber,
c.ThreeCantonNumber, a.FirstCantonName,
b.SecondCantonName,
c.ThreeCantonName
FROM dbo.T_FirstCanton a LEFT OUTER JOIN
dbo.T_SecondCanton b ON
a.FirstCantonNumber = b.FirstCantonNumber LEFT
OUTER JOIN
dbo.T_ThreeCanton c ON
b.SecondCantonNumber = c.SecondCantonNumber
) as a --别名

------解决方案--------------------------------------------------------

SELECT ThreeCantonNumber as areano,ThreeCantonName,(FirstCantonName+SecondCantonName+ThreeCantonName) as AreaName from
(
SELECT a.FirstCantonNumber,
b.SecondCantonNumber,
c.ThreeCantonNumber, a.FirstCantonName,
b.SecondCantonName,
c.ThreeCantonName
FROM dbo.T_FirstCanton a LEFT OUTER JOIN
dbo.T_SecondCanton b ON
a.FirstCantonNumber = b.FirstCantonNumber LEFT
OUTER JOIN
dbo.T_ThreeCanton c ON
b.SecondCantonNumber = c.SecondCantonNumber
) AS T

------解决方案--------------------------------------------------------

SELECT c.ThreeCantonNumber as areano,c.ThreeCantonName,(a.FirstCantonName+b.SecondCantonName+c.ThreeCantonName) as AreaName from(
SELECT a.FirstCantonNumber,
b.SecondCantonNumber,
c.ThreeCantonNumber, a.FirstCantonName,
b.SecondCantonName,
c.ThreeCantonName
FROM dbo.T_FirstCanton a LEFT OUTER JOIN
dbo.T_SecondCanton b ON
a.FirstCantonNumber = b.FirstCantonNumber LEFT
OUTER JOIN
dbo.T_ThreeCanton c ON
b.SecondCantonNumber = c.SecondCantonNumber
)tt

------解决方案--------------------------------------------------------
直接

SELECT c.ThreeCantonNumber as areano,c.ThreeCantonName,(a.FirstCantonName+b.SecondCantonName+c.ThreeCantonName) as AreaName
FROM dbo.T_FirstCanton a LEFT OUTER JOIN
dbo.T_SecondCanton b ON
a.FirstCantonNumber = b.FirstCantonNumber LEFT
OUTER JOIN
dbo.T_ThreeCanton c ON
b.SecondCantonNumber = c.SecondCantonNumber

------解决方案--------------------------------------------------------
子查询必须别名

SELECT ThreeCantonNumber as areano,ThreeCantonName,(FirstCantonNameA+SecondCantonNameB+ThreeCantonNameC) as AreaName from
(
SELECT a.FirstCantonNumber,
b.SecondCantonNumber,
c.ThreeCantonNumber, a.FirstCantonName AS FirstCantonNameA ,
b.SecondCantonName AS FirstCantonNameB  ,
c.ThreeCantonName AS FirstCantonNameC
FROM dbo.T_FirstCanton a LEFT OUTER JOIN
dbo.T_SecondCanton b ON
a.FirstCantonNumber = b.FirstCantonNumber LEFT
OUTER JOIN
dbo.T_ThreeCanton c ON
b.SecondCantonNumber = c.SecondCantonNumber
) AS T

具体请点击：http://www.verydemo.com/demo_c92_i72145.html