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C语言实现通用链表初步(三)----单元测试

2014-05-19 10:36 459 查看
前两节,我们已经完成了链表的一些操作,快来测试一下吧。

这里使用的单元测试工具名字叫“check”。

START_TEST(my_slist_1)
{
struct student students[8] = {{"WangDong",18},{"LiuMing",19},{"SunYazhou",21},{"ChenYu",27},{"LiuXuewei",28},\
{"ZhangGuorong",47},{"LiuDehua",53},{"WangGuozhen",48}};
struct slist_info list;
slist_init(&list);
int i = 0;
for(;i<sizeof(students)/sizeof(students[0]);++i)
list.insert_head(students+i,&list);
list.for_each(&list,print_student);

我们先定义了一个数组,里面存放了姓名,年龄。接下来定义一个链表,并初始化。然后调用插入方法,依次插入。遍历一下,打印出来:

void print_student(void *data)
{
struct student *p = data;
printf("Name: %15s  Age:%d\n",p->name,p->age);

}


用到了这个回调函数。看看打印的结果:

Name: WangGuozhen Age:48

Name: LiuDehua Age:53

Name: ZhangGuorong Age:47

Name: LiuXuewei Age:28

Name: ChenYu Age:27

Name: SunYazhou Age:21

Name: LiuMing Age:19

Name: WangDong Age:18

接着刚才这个测试用例,
struct node_info *p = list.find(&list,compare_student,&students[3]);
list.del(p,&list);
list.for_each(&list,print_student);


我们寻找某个节点(ChenYu),然后删除。

比较的回调函数是:

int compare_student(void *dest,void *src)
{
struct student *p1 = dest;
struct student *p2 = src;
if(strcmp(p1->name,p2->name)==0)
return 1;
else
return 0;
}


结果如图:

Name: WangGuozhen Age:48

Name: LiuDehua Age:53

Name: ZhangGuorong Age:47

Name: LiuXuewei Age:28

Name: SunYazhou Age:21

Name: LiuMing Age:19

Name: WangDong Age:18

再测试一下反转:

list.invert(&list);
list.for_each_safe(&list,print_student);
}
END_TEST


结果是:

Name: WangDong Age:18

Name: LiuMing Age:19

Name: SunYazhou Age:21

Name: LiuXuewei Age:28

Name: ZhangGuorong Age:47

Name: LiuDehua Age:53

Name: WangGuozhen Age:48

测试成功!
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