您的位置:首页 > 理论基础 > 数据结构算法

LeetCode 1 Reverse Words in a String

2014-05-18 15:52 344 查看

题目 Reverse Words in a String

Given an input string, reverse the string word by word.

For example,

Given s = "the sky is blue",

return "blue is sky the".

Clarification:

What constitutes a word?

A sequence of non-space characters constitutes a word.

Could the input string contain leading or trailing spaces?

Yes. However, your reversed string should not contain leading or trailing spaces.

How about multiple spaces between two words?

Reduce them to a single space in the reversed st

思路:首先将原始字符串按照word切分成单词数组,然后将单词数组逆序使用空格连接起来。
class Solution {
public:
vector<string> split(const string &s, char c) {
vector<string> v;

int start = -1;
bool flag = false;
for(int i = 0; i < s.length(); i ++){
if(flag == false) {
if(s[i] != c) {
start = i;
flag = true;
}
}
else {
if(s[i] == c){
flag = false;
v.push_back(s.substr(start, i - start));
}
}
}
if(flag){
v.push_back(s.substr(start, s.length() - start));
}
return v;
}
void reverseWords(string &s) {
vector<string> substrings = split(s, ' ');
s.erase();
if(substrings.size() > 0) {
for(vector<string>::reverse_iterator rit = substrings.rbegin(); rit != substrings.rend(); rit ++) {
s += *rit;
s.push_back(' ');
}
s.pop_back();
}
}
};






内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息