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sql一般操作

2014-05-17 21:18 363 查看
drop table if exists stu;

create table stu(

name varchar(30),

age int,

stuid int not null PRIMARY key AUTO_INCREMENT,

idnum int,

sex varchar(30),

check(sex in ('男','女'))

)charset=utf8;

insert into stu (name,age,idnum,sex)VALUES('damon',789,4678945,'男');

insert into stu (name,age,idnum,sex) VALUES('coco',13,345,'女');

insert into stu (name,age,idnum,sex)values('kitty',13,46,'女');

insert into stu (name,age,idnum,sex)values('alice',14,123,'女');

SELECT * from stu;

select * from stu limit 0,2;

select * from stu where name like '%ce';

select * from stu where name REGEXP "a[sfdl][^ads]";

select * from stu where name in ('damon','alice');

select * from stu where name BETWEEN 'coco' and 'kitty';

select * from stu where name not between 'coco' and 'kitty';

select name as stuname,stuid as id from stu;

drop view if EXISTS young_stu;

create view young_stu as

select name,age from stu where age between 10 and 20;

select * from young_stu where age is not null;
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