Leetcode 线性表 Remove Duplicates from Sorted Array II
2014-05-14 10:54
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本文为senlie原创,转载请保留此地址:http://blog.csdn.net/zhengsenlie
Total Accepted: 10649 Total
Submissions: 35325
Follow up for "Remove Duplicates":
What if duplicates are allowed at most twice?
For example,
Given sorted array A =
Your function should return length =
and A is now
题意:从一个已排序的数组中移除掉重复的元素,每个元素最多可重复两次
思路: 思路和Remove Duplicates from Sorted Array一样,不过要设置一个计数变量,表示当前值出现的次数
出现次数少于2可以加入到新数组,多于2则不可以。每次遇到一个新变量要把计数变量重新设置为1,加入新数组要加1
复杂度:时间O(n), 空间O(1)
相关题目:
class Solution {
public:
int removeDuplicates(int A[], int n){
if (n < 1) return 0;
int c = 1;
int j = 1;
for(int i = 1; i < n; i++){
if (A[i] == A[i - 1]){
if(c < 2){
A[j++] = A[i];
c++;
}
}else{
A[j++] = A[i];
c = 1;
}
}
return j;
}
};
Remove Duplicates from Sorted Array II
Total Accepted: 10649 TotalSubmissions: 35325
Follow up for "Remove Duplicates":
What if duplicates are allowed at most twice?
For example,
Given sorted array A =
[1,1,1,2,2,3],
Your function should return length =
5,
and A is now
[1,1,2,2,3].
题意:从一个已排序的数组中移除掉重复的元素,每个元素最多可重复两次
思路: 思路和Remove Duplicates from Sorted Array一样,不过要设置一个计数变量,表示当前值出现的次数
出现次数少于2可以加入到新数组,多于2则不可以。每次遇到一个新变量要把计数变量重新设置为1,加入新数组要加1
复杂度:时间O(n), 空间O(1)
相关题目:
class Solution {
public:
int removeDuplicates(int A[], int n){
if (n < 1) return 0;
int c = 1;
int j = 1;
for(int i = 1; i < n; i++){
if (A[i] == A[i - 1]){
if(c < 2){
A[j++] = A[i];
c++;
}
}else{
A[j++] = A[i];
c = 1;
}
}
return j;
}
};
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