递归法求解汉罗塔hanoi问题

#include<iostream>
using namespace std;
//汉罗塔递归求解函数 从a移到c
void move(int m,char a,char c);
void hanoi(int n,char a,char b,char c)
{
if(1==n)
{
move(n,a,c);
return;
}
hanoi(n-1,a,c,b);
move(n,a,c);
hanoi(n-1,b,a,c);
}
//将编号为m的圆盘从a移到c
void move(int m,char a,char c)
{
cout<<m<<" : "<<a<<"---->"<<c<<endl;
}
int main()
{
char a = 'A',b = 'B',c = 'C';
hanoi(3,a,b,c);
return 0;
}