[LeetCode] Merge Sorted Array
2014-05-01 00:32
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Problem
: Given two sorted integer arrays A and B, merge B into A as one sorted array.
Note : You may assume that A has enough space (size that is greater or equal tom +n) to hold additional elements from B. The number of elements initialized in A and B arem andn respectively.
1.C++版
2.Java版
3.Python版
完
: Given two sorted integer arrays A and B, merge B into A as one sorted array.
Note : You may assume that A has enough space (size that is greater or equal tom +n) to hold additional elements from B. The number of elements initialized in A and B arem andn respectively.
1.C++版
class Solution { public: void merge(int A[], int m, int B[], int n) { int length=m+n; int *result = new int[length]; int i=0,j=0,k=0; while(i<m && j<n){ if(A[i]<=B[j]){ result[k++]=A[i++]; }else{ result[k++]=B[j++]; } } while(i<m){ result[k++]=A[i++]; } while(j<n){ result[k++]=B[j++]; } for(int i=0;i<length;++i){ A[i]=result[i]; } delete []result; } };
2.Java版
public class Solution { public void merge(int A[], int m, int B[], int n) { int length=m+n; int[] result=new int[length]; int i=0,j=0,k=0; while(i<m && j<n){ if(A[i]<B[j]){ result[k++]=A[i++]; }else{ result[k++]=B[j++]; } } while(i<m){ result[k++]=A[i++]; } while(j<n){ result[k++]=B[j++]; } for(int index=0;index<length;++index){//Java不允许有相同名称的变量出现在同一个方法体中,这是其与C++的不同之处,请注意!!! A[index]=result[index]; } } }
3.Python版
完
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