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POJ 2886 Who Gets the Most Candies?

2014-04-25 10:18 176 查看
线段树 + 反素数。写的很挫。。。不过1A,嘿嘿。

#include <cstdio>
#include <iostream>
#include <cstring>
#include <algorithm>
#include <cmath>
using namespace std;
#define lson l, m, rt << 1
#define rson m + 1, r, rt << 1 | 1
#define N 500006
int n, k;
char a
[100];
int b
;
int pri[20] = {2, 3, 5, 7, 11, 13, 17, 23, 29};
__int64 bestnum;
__int64 bestsum;
int id;
void getNum(__int64 num, __int64 k, __int64 sum){
if(num > n)return ;
if(sum > bestsum){
bestsum = sum;
bestnum = num;
}
else if(sum == bestsum && num < bestnum){
bestnum = num;
}
if(k > 7)return ;
for(int i = 1; num <= n; i++){
num *= pri[k];
getNum(num, k + 1, sum * (i + 1));
}
}
int s[N << 2];
void build(int l, int r, int rt){
s[rt] = r - l + 1;
if(l == r)return ;
int m = (l + r) >> 1;
build(lson);
build(rson);
}
void query(int d, int l, int r, int rt){
if(l == r){id = l; return;}
int m = (l + r) >> 1;
if(s[rt << 1] >= d)query(d, lson);
else query(d - s[rt << 1], rson);
}
int position(int d, int l, int r, int rt){
if(l == r)return s[rt];
int m = (l + r) >> 1;
if(d <= m)return position(d, lson);
else return s[rt << 1] + position(d, rson);
}
void dec(int d, int l, int r, int rt){
s[rt]--;
if(l == r) return ;
int m = (l + r) >> 1;
if(d <= m)dec(d, lson);
else dec(d, rson);
}
int main(){
while(scanf("%d%d", &n, &k) != EOF){
getNum(1, 0, 1);
for(int i = 1; i <= n; i++){
scanf("%s%d", a[i], &b[i]);
}
build(1, n, 1);
int p = k;
int v = k;
for(int i = 1; i < bestnum; i++){
dec(p, 1, n, 1);
if(b[p] > 0)b[p] += v - 1;
else b[p] += v;
b[p] %= s[1];
if(b[p] <= 0)b[p] += s[1];
query(b[p], 1, n, 1);
p = id;
v = position(p, 1, n, 1);
}
printf("%s %I64d\n", a[id], bestsum);
}
return 0;
}
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