UVa 414 - Machined Surfaces
2014-04-19 23:57
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13520498 | 414 | Machined Surfaces | Accepted | ANSI C | 0.009 | 2014-04-19 23:52:55 |
有几组 N行*25个字符的“图片”(以字符“X”为内容),每行中间有裂缝(空格),求出将图片“拼”成一起后剩下的缝隙大小(空格数)。
【解决过程】
思路:求出图片中每行X的最大个数max和N行X的总数sum,max*N-sum即为所求。代码如下:
#include<stdio.h> #include<string.h> int main(){ int n; while(scanf("%d",&n)==1){ int i,j,num ,sum=0,max=-1; for(i=1;i<=n;i++){ char c; memset(num,0,sizeof(num)); for(j=1;j<=25;j++) if((c=getchar())=='X') num[i-1]++; getchar(); if(num[i-1]>max) max=num[i-1]; sum+=num[i-1]; } if(n>0) printf("%d\n",n*max-sum); } return 0; }【教训】
1、输入数据时注意如果用getchar()要在读取每行25个字符后再读一次'\n'。
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