[ACM_水题] UVA 12502 Three Families [2人干3人的活后分钱，水]

Three Families

Three families share a garden. They usually clean the garden together at the end of each week, but last week, family C was on holiday, so family A spent 5 hours, family B spent 4 hours and had everything done. After coming back, family C is willing to pay $90 to the other two families. How much should family A get? You may assume both families were cleaning at the same speed.$90/(5+4)*5=$50? No no no. Think hard. The correct answer is $60. When you figured out why, answer the following question: If family A and B spent x and y hours respectively, and family C paid $z, how much should family A get? It is guaranteed that both families should get non-negative integer dollars.WARNING: Try to avoid floating-point numbers. If you really need to, be careful!

Input

The first line contains an integer T ( T

100), the number of test cases. Each test case contains three integers x, y, z ( 1

x, y

10, 1

z

1000).

Output

For each test case, print an integer, representing the amount of dollars that family A should get.

Sample Input

2
5 4 90
8 4 123

Sample Output

60
123

题目大意：水题，不解释。推出计算公式瞬秒！

#include<iostream>
#include<cstdio>
using namespace std;
int main(){
int T;cin>>T;
while(T--){
int x,y,z;
cin>>x>>y>>z;
cout<<(3*x*z)/(x+y)-z<<'\n';
}return 0;
}