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HDU 2202 最大三角形

2014-04-07 13:54 246 查看
题解:先算出凸包,然后枚举凸包上的点计算即可

#include <cstdio>
#include <cmath>
#include <cstdlib>
#include <iostream>
using namespace std;
const int N = 50005;
const double eps = 1e-8;
struct point {int x,y;}p
, stack
;
bool isZero(double x){return (x>0?x:-x)<eps;}
double dis(point A, point B){return sqrt((A.x-B.x)*(A.x-B.x)+(A.y-B.y)*(A.y-B.y));}
int crossProd(point A, point B, point C){return (B.x-A.x)*(C.y-A.y)-(B.y-A.y)*(C.x-A.x);}
int cmp(const void *a, const void *b){
point*c=(point*)a;
point*d=(point*)b;
double k = crossProd(p[0], *c, *d);
if (kdis(p[0], *d))) return 1;
return -1;
}
int Graham(int n) {
int x = p[0].x;
int y = p[0].y;
int mi = 0;
for (int i=1; i<n; ++i) {
if (p[i].x=2)--top;
stack[++top]=p[i];
}
return top;
}
double maxTrangle(int n) {
int top=Graham(n);
double area,maxArea = 0;
for (int i=0;i<top;++i) {
for (int j=i+1;j<top;++j) {
for (int k=j+1;k<=top;++k) {
area=crossProd(stack[i],stack[j],stack[k]);
if (maxArea<area) maxArea=area;
}
}
}
return maxArea*0.5;
}
int main() {
int n;
while (scanf("%d", &n) != EOF) {
for (int i=0; i<n; ++i) scanf ("%d%d", &p[i].x, &p[i].y);
double ans = maxTrangle(n);
printf ("%.2lf\n", ans);
}
return 0;
}
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