UVA - 494 - Kindergarten Counting Game
2014-04-06 21:30
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http://uva.onlinejudge.org/index.php?option=com_onlinejudge&Itemid=8&category=94&page=show_problem&problem=435
题意:
在输入的字符串中,判断有多少个单词,连续的字母排序组成单词,也就是说,其它非字母的都是分隔符。
解题:直接针对输入的每个字符进行判断,如果是回车或非字母,直接统计单词数量。
(当然中间要有个iFlagLastLetter值用来记录上一个字符是不是字母)
题意:
在输入的字符串中,判断有多少个单词,连续的字母排序组成单词,也就是说,其它非字母的都是分隔符。
解题:直接针对输入的每个字符进行判断,如果是回车或非字母,直接统计单词数量。
(当然中间要有个iFlagLastLetter值用来记录上一个字符是不是字母)
#include <iostream> #include <stdio.h> using namespace std; int main() { char ch; int nCount; int iFlagLastLetter; nCount = 0; iFlagLastLetter = 0; while ( (ch = cin.get() ) != EOF ) { if ( ch == '\0' ) { break; } // end if else { if ( ch == '\n' ) { if ( iFlagLastLetter == 1 ) { nCount ++; } // end if cout <<nCount <<endl; nCount = 0; iFlagLastLetter = 0; } // end if else { if ( !isalpha(ch) ) { if ( iFlagLastLetter == 1 ) { nCount++; } // end if iFlagLastLetter = 0; } // end if else { iFlagLastLetter = 1; } // end else } // end else } // end else } // end while return 0; }
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