hdu 1037 Keep on Truckin'(水题)
2014-04-05 13:50
316 查看
小记:题目描述的太多废话了,而且我也没全看,只看了which means its... 然后大概理解觉得应该是这样的,然后就开始码,结果对了。
思路:输入只要3个数,从左到右只要大于168就输出CRASH + 这个数,如果没有即都大于168就输出NO CRASH。
代码:
#include <iostream>
using namespace std;
int main(){
int n, m, k;
while(cin>>n>>m>>k){
if(n<=168){
cout << "CRASH "<<n<< endl;
}
else if(m <= 168){
cout << "CRASH "<<m<< endl;
}
else if(k <= 168){
cout << "CRASH "<<k<< endl;
}
else {
cout<<"NO CRASH"<<endl;
}
}
return 0;
}
思路:输入只要3个数,从左到右只要大于168就输出CRASH + 这个数,如果没有即都大于168就输出NO CRASH。
代码:
#include <iostream>
using namespace std;
int main(){
int n, m, k;
while(cin>>n>>m>>k){
if(n<=168){
cout << "CRASH "<<n<< endl;
}
else if(m <= 168){
cout << "CRASH "<<m<< endl;
}
else if(k <= 168){
cout << "CRASH "<<k<< endl;
}
else {
cout<<"NO CRASH"<<endl;
}
}
return 0;
}
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