HDU 2222 Keywords Search AC自动机入门模版题
2014-04-01 11:05
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Total Submission(s): 30691 Accepted Submission(s): 9999
[align=left]Problem Description[/align]
In the modern time, Search engine came into the life of everybody like Google, Baidu, etc.
Wiskey also wants to bring this feature to his image retrieval system.
Every image have a long description, when users type some keywords to find the image, the system will match the keywords with description of image and show the image which the most keywords be matched.
To simplify the problem, giving you a description of image, and some keywords, you should tell me how many keywords will be match.
[align=left]Input[/align]
First line will contain one integer means how many cases will follow by.
Each case will contain two integers N means the number of keywords and N keywords follow. (N <= 10000)
Each keyword will only contains characters 'a'-'z', and the length will be not longer than 50.
The last line is the description, and the length will be not longer than 1000000.
[align=left]Output[/align]
Print how many keywords are contained in the description.
[align=left]Sample Input[/align]
1
5
she
he
say
shr
her
yasherhs
[align=left]Sample Output[/align]
3
[align=left]Author[/align]
Wiskey
给你n个单词,然后一个文本串,让你在这个文本串里面找出现了几个单词。
AC自动机入门,详解:点击打开链接
Keywords Search
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others)Total Submission(s): 30691 Accepted Submission(s): 9999
[align=left]Problem Description[/align]
In the modern time, Search engine came into the life of everybody like Google, Baidu, etc.
Wiskey also wants to bring this feature to his image retrieval system.
Every image have a long description, when users type some keywords to find the image, the system will match the keywords with description of image and show the image which the most keywords be matched.
To simplify the problem, giving you a description of image, and some keywords, you should tell me how many keywords will be match.
[align=left]Input[/align]
First line will contain one integer means how many cases will follow by.
Each case will contain two integers N means the number of keywords and N keywords follow. (N <= 10000)
Each keyword will only contains characters 'a'-'z', and the length will be not longer than 50.
The last line is the description, and the length will be not longer than 1000000.
[align=left]Output[/align]
Print how many keywords are contained in the description.
[align=left]Sample Input[/align]
1
5
she
he
say
shr
her
yasherhs
[align=left]Sample Output[/align]
3
[align=left]Author[/align]
Wiskey
给你n个单词,然后一个文本串,让你在这个文本串里面找出现了几个单词。
AC自动机入门,详解:点击打开链接
//234MS 29364K #include<stdio.h> #include<string.h> char str[1000007]; int head,tail;//队列的头和尾 struct node { node *next[26];//Trie每个节点的26个字节点 node *fail;//失效指针 int count;//是否为该单词的最后一个节点 node()//构造函数初始化 { count=0; fail=NULL; memset(next,0,sizeof(next)); } } *q[500001];//队列,方便用于bfs构造失效指针 void insert(node *root) { node *p=root; int i=0,index; while(str[i]) { index=str[i]-'a'; if(p->next[index]==NULL)p->next[index]=new node(); p=p->next[index]; i++; } p->count++;//在单词的最后一个节点count+1,代表一个单词 } void build_ac(node *root) { root->fail=NULL; q[head++]=root; while(head!=tail) { node *temp=q[tail++]; node *p=NULL; for(int i=0;i<26;i++) { if(temp->next[i]!=NULL) { if(temp==root)temp->next[i]->fail=root; else { p=temp->fail; while(p!=NULL) { if(p->next[i]!=NULL) { temp->next[i]->fail=p->next[i]; break; } p=p->fail; } if(p==NULL)temp->next[i]->fail=root; } q[head++]=temp->next[i]; } } } } int query(node *root) { int i=0,cnt=0,index; node *p=root; while(str[i]) { index=str[i]-'a'; while(p->next[index]==NULL&&p!=root)p=p->fail; p=p->next[index]; p=(p==NULL)?root:p; node *temp=p; while(temp!=root&&temp->count!=-1) { cnt+=temp->count; temp->count=-1; temp=temp->fail; } i++; } return cnt; } int main() { int t,n; scanf("%d",&t); while(t--) { head=tail=0; node *root=new node(); scanf("%d",&n); while(n--) { scanf("%s",str); insert(root); } build_ac(root); scanf("%s",str); printf("%d\n",query(root)); } return 0; }
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