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[Leetcode] Path Sum

2014-03-31 01:08 190 查看
Given a binary tree and a sum, determine if the tree has a root-to-leaf path such that adding up all the values along the path equals the given sum.

For example:
Given the below binary tree and
sum = 22
,

5
/ \
4   8
/   / \
11  13  4
/  \      \
7    2      1

return true, as there exist a root-to-leaf path
5->4->11->2
which sum is 22.

水!

/**
* Definition for binary tree
* struct TreeNode {
*     int val;
*     TreeNode *left;
*     TreeNode *right;
*     TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
public:
bool hasPathSum(TreeNode *root, int sum) {
if (root == NULL) {
return false;
}
if (root->left == NULL && root->right == NULL) {
return root->val == sum;
}
bool flag1 = hasPathSum(root->left, sum - root->val);
bool flag2 = hasPathSum(root->right, sum - root->val);
return flag1 || flag2;
}
};
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