自定义RFS关键字库中的关键字（使用python随机生成身份证号码）

在使用齐道长的QTLibrary时，发现他定义的身份证生成的关键字方法并不能满足我的需求，

于是我在_element.py中重写了一个gen_idcard_new方法

import time
import random
import sys
reload(sys)
sys.setdefaultencoding('utf-8')

def gen_idcard_new(self, idcard=''):
"""Get newidcard No.
Example:
| ${a}= | gen newidcard | 123 |
It will return random idcard.
like '111110198101010231'.
"""
ARR = (7, 9, 10, 5, 8, 4, 2, 1, 6, 3, 7, 9, 10, 5, 8, 4, 2)
pro = {
0: '11',
1: '12',
2: '13',
3: '14',
4: '15',
5: '21',
6: '22',
7: '23',
8: '31',
9: '32',
10: '33',
11: '34',
12: '35',
13: '36',
14: '37',
15: '41',
16: '42',
17: '43',
18: '44',
19: '45',
20: '46',
21: '50',
22: '51',
23: '52',
24: '53',
25: '54',
26: '61',
27: '62',
28: '63',
29: '64',
30: '65'
}

LAST = {
0: '1',
1: '0',
2: 'x',
3: '9',
4: '8',
5: '7',
6: '6',
7: '5',
8: '4',
9: '3',
10: '2'
}

t = time.localtime()[0]
x = '%02d%02d%02d%04d%02d%02d%03d' % (pro[random.randint(0, 30)],
random.randint(01, 99),
random.randint(01, 99),
random.randint(t - 80, t - 18),
random.randint(1, 12),
random.randint(1, 28),
random.randint(1, 999))
y = 0
for i in range(17):
y += int(x[i]) * ARR[i]
b = y % 11
return '%s%s' % (x, LAST[b])

完成后更新源文件，重新install即可看到新方法。

其中遇到了问题，python对格式缩进要求很严格，而一般编辑器对空格和tab的辨识度基本没有，

所以推荐一款python用的工具PyCharm

用户名：yueting3527

注册码： ===== LICENSE BEGIN =====

93347-12042010 00001FMHemWIs"6wozMZnat3IgXKXJ 2!nV2I6kSO48hgGLa9JNgjQ5oKz1Us FFR8k"nGzJHzjQT6IBG!1fbQZn9!Vi

===== LICENSE END =====