LINUX FTP安装与配置

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/**==** 2. 随机排序中的newid()问题 **==**/
--测试数据
declare @t table(name char(1),value int)
insert into @t
select 'a',1
union all select 'a',2
union all select 'b',3
union all select 'b',4
union all select 'c',5
union all select 'c',6

--要求,随机排序,但name相同的要排在一齐
select a.*
from @t a join(
select aa=newid(),name from(select distinct name from @t) a
) b on a.name=b.name
order by b.aa,newid()

/*--测试结果之一,并没有达到要求.如果将join改成left right full join,就正确
name value
---- -----------
b 4
b 3
c 5
a 1
a 2
c 6

（所影响的行数为 6 行）
--*/

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