统计出生天数（改进前）

#include<stdio.h>

int birthdays();//计算从出生日到现在的总天数
int sum();//计算某一年到某一年的总天数
int count();//计算闰年与非闰年某一天为该年第几天
int	number();//计算第n月m天为该年第几天的函数
int check();
int door=0;

int main()
{
int Year1;
int Month1;
int Date1;
int Year2;
int Month2;
int Date2;
int Days=0;
printf("请输入您的出生日期:year-math-day\n");
scanf("%d-%d-%d",&Year1,&Month1,&Date1);
printf("请输入您当前的日期:\nyear-math-day\n");
scanf("%d-%d-%d",&Year2,&Month2,&Date2);
Days=birthdays(Year1,Year2,Month1,Month2,Date1,Date2);
if(door<=0)
{
printf("今天是你出生后的第%d天",Days);

}

}

int birthdays(int Year1,int Year2,int Month1,int Month2,int Date1,int Date2)
{
int Sumdays;
if(Year1<Year2)
{
Sumdays=sum(Year1,Year2)+count(Year2,Month2,Date2)-count(Year1,Month1,Date1);
return Sumdays;
}
else if(Year1>Year2)
{
printf("输入有误!");
door=1;
}
}

int sum(int Year1,int Year2)
{
int n,Days=0;

for(n=Year1;n<Year2;n++)
{
if (((n%100!=0) && (n%4==0)) || (n%400==0))
{
Days+=366;
}
else
{
Days+=365;
}
}
return Days;
}
int count(int Year,int Month,int Date)
{
int Days=0;
int flg;

if ((Year%100!=0) && (Year%4==0) || (Year%400==0))
{
flg=1;
check(Month,Date,flg);
Days+=number(Month,Date,flg);
}

else
{	flg=0;
check(Month,Date,flg);
Days+=number(Month,Date,flg)-1;
}

return Days;
}

int number(int Month,int Date)
{
int Days=0;
switch (Month)
{
case 1:
Days+=Date;
break;
case 2:
Days=31+Date;
break;
case 3:
Days=60+Date;
break;
case 4:
Days=91+Date;
break;
case 5:
Days=121+Date;
break;
case 6:
Days=152+Date;
break;
case 7:
Days=182+Date;
break;
case 8:
Days=213+Date;
break;
case 9:
Days=244+Date;
break;
case 10:
Days=274+Date;
break;
case 11:
Days=305+Date;
break;
case 12:
Days=335+Date;
break;
default:
printf("您输入的信息有误，请重新输入");
}
return Days;
}

int check(int Month,int Date,int flg)
{
switch (Month)
{
case 1:
if(Date>31)
{
door=1;
}
break;
case 2:
if(flg)
{
if (Date>29)
{
printf("您输入的信息有误闰年2月不会大于29天！");
}				door=1;
}
else if(flg<1)
{
if (Date>28)
{
}
printf("您输入的信息有误！非闰年二月不会大于28天");
door=1;
}
break;
case 3:
if(Date>31)
{
door=1;
}
break;
case 4:
if(Date>30)
{
door=1;
}
break;
case 5:
if(Date>31)
{
door=1;
}
break;
case 6:
if(Date>30)
{
door=1;
}
break;
case 7:
if(Date>31)
{
door=1;
}
break;
case 8:
if(Date>31)
{
door=1;
}
break;
case 9:
if(Date>30)
{
door=1;
}
break;
case 10:
if(Date>31)
{
door=1;
}
break;
case 11:
if(Date>30)
{
door=1;
}
break;
case 12:
if(Date>31)
{
door=1;
}

}
return door;
}