以前写的一些小程序总结

eg 1：

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// small program.cpp : 定义控制台应用程序的入口点。


[code]//

#include "stdafx.h"

#include <stdio.h>

//输出100-200以内所有的素数

int main()

{

int flag = 1,count = 0;

for(int m = 101; m < 200 ;m++)

{

int k = m/2;

for(int i = 2;i < k; i++)

{

if(m % i == 0)

 {

printf("%d 为合数",m);

flag = 0;

break;

}

}

if(flag == 1)

{

printf("%d 为素数 ",m);

count++;

}

flag = 1;

}

printf("\n");

printf("总共有 %d 个素数 ",count);

return 0;

}

[/code]

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font-family: consolas, "Courier New", courier, monospace;
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.csharpcode .rem { color: #008000; }
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.csharpcode .op { color: #0000c0; }
.csharpcode .preproc { color: #cc6633; }
.csharpcode .asp { background-color: #ffff00; }
.csharpcode .html { color: #800000; }
.csharpcode .attr { color: #ff0000; }
.csharpcode .alt
{
background-color: #f4f4f4;
width: 100%;
margin: 0em;
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.csharpcode .lnum { color: #606060; }

 





eg 2：

// small program.cpp : 定义控制台应用程序的入口点。


[code]//

#include "stdafx.h"

#include <stdio.h>

//冒泡排序

int main()

{

int a[10]={1,7,8,3,2,6,5,0,4,9};

int i,j,t;

for( i= 0; i < 10; i++) //控制次数

 {

for( j = 0;j < 10 - i;j ++)//两两交换

 {

if(a[j] < a[j+1])

 {

t = a[j+1];

a[j+1] = a[j];

a[j] = t;

}

 }

 }

for(i = 0; i < 10; i++)

printf("%d ",a[i]);

  printf("\n");

return 0;

}

[/code]

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font-family: consolas, "Courier New", courier, monospace;
background-color: #ffffff;
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.csharpcode .rem { color: #008000; }
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.csharpcode .asp { background-color: #ffff00; }
.csharpcode .html { color: #800000; }
.csharpcode .attr { color: #ff0000; }
.csharpcode .alt
{
background-color: #f4f4f4;
width: 100%;
margin: 0em;
}
.csharpcode .lnum { color: #606060; }

 





 

eg 3:

// small program.cpp : 定义控制台应用程序的入口点。


[code]//

#include "stdafx.h"

#include <stdio.h>

/*有3个学生，每个学生有3门课的成绩，

从键盘输入以上数据（包括学生号，姓名，一门课成绩）,并输出*/

typedef struct Stu

{

 int number;//这里面有一个bug，当我定义char[]时，输入数字会出现问题。理论上讲，数字也是字符才是呀

 char name[3];

 int score;

} Stu;

int main()

{

Stu  stu[3];

printf("请输入3名学生的学号，姓名，成绩\n");

for(int i = 0; i < 3; i++)

{

 scanf("%d",&stu[i].number);

 scanf("%s",&stu[i].name);  

 scanf("%d",&stu[i].score);  

}

 for(int i = 0; i < 3; i++)

{

 printf("%d",stu[i].number);

 printf("%s",stu[i].name);

 printf("%d",stu[i].score);

 printf("\n");

}

printf("\n");

return 0;

}

[/code]

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font-family: consolas, "Courier New", courier, monospace;
background-color: #ffffff;
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.csharpcode .lnum { color: #606060; }

 

/*********************************************************


[code]函数作用：  1、查找中心点的位置,8位AD，共91个点。

计算偏差，偏右为负，偏左为正

规定abs（vedio[i]-vedio[i-1]）>80为黑白交汇处。

2、统计黑区数目，宽度，并保存

3、发现意外情况，返回出错标志供主程序查询

4、规定黑点<2,白点>80

5、假定黑区是连着的。

**********************************************************/

#include <stdio.h>

#include <math.h>

main()

{

 int vedio[91]={0},i,j,m,x,y;

 int l_edge=0,r_edge=0; 

 int blackcount=0; //数黑区数 规定若blackcount大于8为一块黑区。

 int flag,flag2;

 int l[90]={0},r[90]={0};

 printf("请输入91个数：\n");

 for (i=0;i<13;i++)

 { 

  scanf("%d",&vedio[i]);

  printf("%d",vedio[i]);

 }

for(j=0;j<13;j++)

{

if(vedio[j]-vedio[j+1]>80)//白到黑

{

 flag=1;

 flag2=0;

 l_edge=j+1;

 r_edge=l_edge;

}

 else if(vedio[j]-vedio[j+1]<-80)//黑到白

{

  flag=0;

  flag2=1;

}

 else

{

  if(flag==1)

 {

blackcount++;

l_edge++;

}

  if(flag2==1)

 {

  for(m=0;m<90;m++)

{  l[m]=r_edge;

  r[m]=l_edge;}

}

}

}

printf("\n输出blackcount：%d\n",blackcount);

//计算中心点，及黑区的个数。

if (blackcount<8)

 printf("没有黑区\n");

else if(blackcount>=8&&blackcount<15)

{

printf("只有一块黑区\n");

x=(l[0]+r[0])/2;

y=45-x;

 printf("此黑线的中心点为%d\n",y);

}

else if(blackcount>=15&&blackcount<24)

printf("有两块黑区\n");

else if(blackcount>=24&&blackcount<32)

printf("有三块黑区\n");

else printf("出错了\n");

}

[/code]

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font-family: consolas, "Courier New", courier, monospace;
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.csharpcode .html { color: #800000; }
.csharpcode .attr { color: #ff0000; }
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.csharpcode .lnum { color: #606060; }