【c++】PAT(advanced level)1058. A+B in Hogwarts (20)

1058. A+B in Hogwarts (20)

时间限制
50 ms

内存限制
32000 kB

代码长度限制
16000 B

判题程序
Standard

作者
CHEN, Yue

If you are a fan of Harry Potter, you would know the world of magic has its own currency system -- as Hagrid explained it to Harry, "Seventeen silver Sickles to a Galleon and twenty-nine Knuts to a Sickle, it's easy enough." Your job is to write a program
to compute A+B where A and B are given in the standard form of "Galleon.Sickle.Knut" (Galleon is an integer in [0, 107], Sickle is an integer in [0, 17), and Knut is an integer in [0, 29)).

Input Specification:

Each input file contains one test case which occupies a line with A and B in the standard form, separated by one space.

Output Specification:

For each test case you should output the sum of A and B in one line, with the same format as the input.

Sample Input:

3.2.1 10.16.27

Sample Output:

14.1.28

其实就是考输入格式的有木有！！

#include<iostream>
#include<string>
using namespace std;

int main()
{
int a[3],b[3];
char c;
cin>>a[0]>>c>>a[1]>>c>>a[2];
cin>>b[0]>>c>>b[1]>>c>>b[2];
int ff=0;
a[2]=a[2]+b[2];
if(a[2]>=29){
a[1]++;
a[2]-=29;
}
a[1]=a[1]+b[1];
if(a[1]>=17){
a[0]++;
a[1]-=17;
}
a[0]=a[0]+b[0];
cout<<a[0]<<"."<<a[1]<<"."<<a[2];

return 0;
}