pat:1011<advanced> <World Cup>
2014-03-02 23:00
477 查看
http://pat.zju.edu.cn/contests/pat-a-practise/1011
很好的一题。重在思考暗含的数据关系。
所给的测试数据结果应为37.97
很好的一题。重在思考暗含的数据关系。
所给的测试数据结果应为37.97
// PAT,高级题集 // 考察查表及对表中信息的记录 // #include <stdio.h> char map[]={'W' ,'T', 'L'}; int main(){ #ifdef ONLINE_JUDGE #else freopen("E:\\in.txt", "r" , stdin); #endif double a[3][3]; int pos[3]; int row=0; while(scanf("%lf %lf %lf", &a[0][0], &a[0][1], &a[0][2]) != EOF) { int i; for(i=1; i<3; i++) { scanf("%lf %lf %lf", &a[i][0], &a[i][1], &a[i][2]); } int j; for(i=0; i<3; i++) { double max=a[i][0]; pos[i]=0; for(j=1; j<3; j++) { if(a[i][j] > max) { max = a[i][j]; pos[i]=j; } }//pos存放了每行的最大值的下标 } for(i=0; i<3; i++) { printf("%c ", map[pos[i]]); } double ans = (a[0][pos[0]] * a[1][pos[1]] * a[2][pos[2]] * 0.65 - 1.0) * 2.0; printf("%.2lf\n", ans); } return 0; }
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