Ural1574

C - Mathematicians and brackets
Time Limit:1000MS Memory Limit:65536KB 64bit IO Format:%I64d
& %I64u
Submit Status Practice URAL
1574

Description

Once upon a time three mathematicians met…

The first of them wrote a sequence of brackets on a chalkboard.
The second one wondered if there was a cyclic shift turning that sequence into a regular one.
After thinking for a while, the third mathematician told the number of such shifts.

You are given the sequence of brackets written by the first mathematician and you are to find the number told by the third mathematician. A regular sequence of brackets is defined as follows.

An empty string is a regular sequence of brackets.
If a string a is a regular sequence of brackets, then the string (a) is also a regular sequence of brackets.
If strings a and b are regular sequences of brackets, then the string ab is also a regular sequence of brackets.
There are no other regular sequences of brackets.

A string a is a cyclic shift of a string b if a and b have the same lengths and a consists of some (possibly empty) suffix from b followed by a prefix from b.

Input

The only line of the input contains the sequence of brackets written by the first mathematician. The sequence is non-empty and its length doesn't exceed 10 5.

Output

Output the number of cyclic shifts turning the given sequence into a regular one.

Sample Input

input	output
)(()	1
)()(	2
()	1

#include <iostream>
#include <cstdio>
#include <cstring>
#include <string>
using namespace std;
#define MAXN 100010
string input;
int main(){
int len, t, NumShift, vMin;
cin>>input;
len = input.size();
t = 0;
vMin = MAXN;
for(int i = 0; i < len; i++){
if(input[i] == '(') t++;
else if(input[i] == ')') t--;
if(vMin > t) vMin = t;
}
NumShift = 0;
if(t != 0)
cout<<0<<endl;
else {
for(int i = 0; i < len; i++){
if(input[i] == '(') vMin--;
else if(input[i] == ')') vMin++;
if(vMin >= 0) NumShift++;
}
cout<<NumShift<<endl;
}
return 0;
}