二分求值

Can you solve this equation?

Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 32768/32768 K (Java/Others)
Total Submission(s): 6753 Accepted Submission(s): 3151


[align=left]Problem Description[/align]
Now,given the equation 8*x^4 + 7*x^3 + 2*x^2 + 3*x + 6 == Y,can you find its solution between 0 and 100;
Now please try your lucky.

[align=left]Input[/align]
The first line of the input contains an integer T(1<=T<=100) which means the number of test cases. Then T lines follow, each line has a real number Y (fabs(Y) <= 1e10);

[align=left]Output[/align]
For each test case, you should just output one real number(accurate up to 4 decimal places),which is the solution of the equation,or “No solution!”,if there is no solution for the equation between 0 and 100.

[align=left]Sample Input[/align]

2
100
-4

[align=left]Sample Output[/align]

1.6152
No solution!

#include<iostream>
#include<cstdio>
using namespace std;
double f(double m){
return 8 * m*m*m*m + 7 * m*m*m + 2 * m*m + 3 * m + 6;
}
int main()
{
int t;
double y;
cin >> t;
while (t--){
cin >> y;
if (y<f(0) || y>f(100)){ cout << "No solution!\n"; continue; }//没想起来怎么判断，唉
double h = 0, e = 100, m;
for (int i = 0; i < 100; i++){
m = (h + e) / 2;
if ( f(m)< y)h = m;
else e = m;
}
printf("%.4lf\n", m);
}
return 0;
}