读取XML直接转换为类对象

<?xml version="1.0" encoding="utf-8"?>
<ArrayOfMenuItems xmlns:xsi="http://www.w3.org/2001/XMLSchema-instance" xmlns:xsd="http://www.w3.org/2001/XMLSchema">
<MenuItems>
<name>xxx</name>
<menuItemList>
<MenuItem>
<name>xxx1</name>
<moduleNameSpace>ControlsLibrary</moduleNameSpace>
<modulePath>ControlsLibrary.ControlsImp.ExamTest</modulePath>
<configPath>\config\Exam.xml</configPath>
</MenuItem>
<MenuItem>
<name>xxxxa</name>
<moduleNameSpace>ControlsLibrary</moduleNameSpace>
<modulePath>ControlsLibrary.ControlsImp.ExamTest</modulePath>
<configPath>\config\Exam.xml</configPath>
</MenuItem>
<MenuItem>
<name>xxxxa1</name>
<moduleNameSpace>ControlsLibrary</moduleNameSpace>
<modulePath>ControlsLibrary.ControlsImp.ExamTest</modulePath>
<configPath>\config\Exam.xml</configPath>
</MenuItem>
</menuItemList>
</MenuItems>
</ArrayOfMenuItems>

/// <summary>
/// 所有的节点集合
/// </summary>
public static List<MenuItems> menusList { get; set; }

/// <summary>
/// 目录树节点类
/// </summary>
public class MenuItems
{
/// <summary>
/// 节点名
/// </summary>
public string name { get; set; }
/// <summary>
/// 包含的选择项内容
/// </summary>
public List<MenuItem> menuItemList { get; set; }
}

/// <summary>
/// 目录树内容类
/// </summary>
public class MenuItem
{
/// <summary>
/// 菜单名
/// </summary>
public string name { get; set; }
/// <summary>
/// 所调用的类库命名空间
/// </summary>
public string moduleNameSpace { get; set; }
/// <summary>
/// 所调用的类库路径
/// </summary>
public string modulePath { get; set; }
/// <summary>
/// 类库所调用的配置文件路径
/// </summary>
public string configPath { get; set; }
}

/// <summary>
/// 从磁盘读取配置文件信息
/// </summary>
/// <param name="type"></param>
/// <param name="txtFilePath">配置文件路径</param>
/// <returns></returns>
public static object ReadConfig<T>(T obj, string filePath)
{

StreamReader fileStream =new StreamReader( filePath);
string  configtxt = fileStream.ReadToEnd();
fileStream.Close();
using (StringReader reader = new StringReader(configtxt))
{
return new XmlSerializer(typeof(T)).Deserialize(reader);
}
}

PsyAdjust.Common.Module.Menu.menusList = PsyAdjust.Common.Module.ObjectConvert.ReadConfig(PsyAdjust.Common.Module.Menu.menusList, "Menue.xml") as List<PsyAdjust.Common.Module.Menu.MenuItems>;