您的位置:首页 > 其它

SRM 599 D2L2:BigFatInteger2, math

2014-02-17 00:03 246 查看
题目:http://community.topcoder.com/stat?c=problem_statement&pm=12870

代码:

#include <algorithm>
#include <functional>
#include <numeric>
#include <utility>
#include <iostream>
#include <sstream>
#include <iomanip>

#include <bitset>
#include <string>
#include <vector>
#include <stack>
#include <deque>
#include <queue>
#include <set>
#include <map>

#include <cstdio>
#include <cstdlib>
#include <cctype>
#include <cmath>
#include <cstring>
#include <ctime>
#include <climits>

using namespace std;

#define CHECKTIME() printf("%.2lf\n", (double)clock() / CLOCKS_PER_SEC)

/*************** Program Begin **********************/

class BigFatInteger2 {
public:
map < long long, long long > extractPrimeFactors(int x)
{
map <long long, long long> ap;
for (int p = 2; p * p <= x; p++) {
int ex = 0;
bool flag = false;
while (x % p == 0) {
flag = true;
++ex;
x /= p;
}
if (flag) {
ap[p] = ex;
}
}
if (x != 1) {
ap[x] = 1;
}
return ap;
}

string isDivisible(int A, int B, int C, int D) {
auto ap = extractPrimeFactors(A);
auto cp = extractPrimeFactors(C);
for (auto it = cp.begin(); it != cp.end(); it++) {
if (ap[ (*it).first ] * B < (*it).second * D) {
return "not divisible";
}
}
return "divisible";
}

};

/************** Program End ************************/
内容来自用户分享和网络整理,不保证内容的准确性,如有侵权内容,可联系管理员处理 点击这里给我发消息
标签: