hdu-3518-Boring counting
2014-02-12 09:49
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枚举子串的长度,。。
#include <stdio.h> #include <math.h> #include <string.h> #include <algorithm> #include <iostream> using namespace std; #define inf 0x3f3f3f3f const int N = 1100; int r , tx , ty , rs , ranks , sa , height , rmq [20]; //rs基数排序 char s ; bool cmp(int *r, int a, int b, int len) { return (r[a] == r[b]) && (r[a + len] == r[b + len]); } void suffix(int n, int m) //n为长度,最大值小于m { int i, j, p, *x = tx, *y = ty, *t; for(i = 0; i < m; ++i) rs[i] = 0; for(i = 0; i < n; ++i) { x[i] = r[i]; ++rs[x[i]]; } for(i = 1; i < m; ++i) rs[i] += rs[i - 1]; for(i = n - 1; i >= 0; --i) sa[--rs[x[i]]] = i; for(j = p = 1; p < n; j <<= 1, m = p) { for(p = 0, i = n - j; i < n; ++i) y[p++] = i; for(i = 0; i < n; ++i) { if(sa[i] >= j) y[p++] = sa[i] - j; } for(i = 0; i < m; ++i) rs[i] = 0; for(i = 0; i < n; ++i) ++rs[x[y[i]]]; for(i = 1; i < m; ++i) rs[i] += rs[i - 1]; for(i = n - 1; i >= 0; --i) sa[--rs[x[y[i]]]] = y[i]; t = x, x = y, y = t; for(i = 1, p = 1, x[sa[0]] = 0; i < n; ++i) { if(cmp(y, sa[i - 1], sa[i], j)) x[sa[i]] = p - 1; else x[sa[i]] = p++; } } /**for(i = 0; i < n; ++i) printf("%s\n", s + sa[i]);*/ } void calheight(int n) { int i, j, k = 0; for(i = 1; i <= n; ++i) ranks[sa[i]] = i; for(i = 0; i < n; ++i) { if(k) --k; j = sa[ranks[i] - 1]; while(r[i + k] == r[j + k]) ++k; height[ranks[i]] = k; } } int main() { while(scanf("%s",s)) { int i,j,k; int len=strlen(s); if(len==1 && s[0]=='#') break; for(i=0;i<len;i++) r[i]=s[i]; r[len]=0; suffix(len+1,130); calheight(len); int sum=0; for(j=1;j<=len/2;j++) { int mx=sa[1],mn=sa[1]; for(i=2;i<=len;i++) { while(1) { if(height[i]>=j) { mx=max(mx,sa[i]); mn=min(mn,sa[i]); i++; if(i>len) break; } else break; } if(mx-mn>=j) sum++; mx=sa[i],mn=sa[i]; } } cout<<sum<<endl; } }
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