An Easy Task

Description

Ignatius was born in a leap year, so he want to know when he could hold his birthday party. Can you tell him?

Given a positive integers Y which indicate the start year, and a positive integer N, your task is to tell the Nth leap year from year Y.

Note: if year Y is a leap year, then the 1st leap year is year Y.

Input

The input contains several test cases. The first line of the input is a single integer T which is the number of test cases. T test cases follow.

Each test case contains two positive integers Y and N(1<=N<=10000).

Output

For each test case, you should output the Nth leap year from year Y.

Sample Input

3
2005 25
1855 12
2004 10000

Sample Output

2108
1904
43236

Hint
We call year Y a leap year only if (Y%4==0 && Y%100!=0) or Y%400==0.

#include<stdio.h>
int main()
{
int m,n,i,j,year;
scanf("%d",&m);
while(m--)
{
scanf("%d%d",&year,&n);
int s=1;
while(s<=n)
{
if(year%4==0&&year%100!=0||year%400==0)
s++;
year++;
}
printf("%d\n",year-1);
}
return 0;
}