NYOJ-214 单调递增子序列(二) TLE 分类： NYOJ 2014-01-28 22:57 171人阅读 评论(0) 收藏

#include<stdio.h>
#include<stdlib.h>
#define max(x,y)	x>y?x:y
#define MAXX 100005
int num[MAXX] = {0};
int mum[MAXX] = {0};
int sum[2][MAXX] = {0};

int comp ( const void *a, const void *b )
{
return * ( int * ) a - * ( int * ) b;
}

int main(){
int n, i, j, k, d;

while(scanf("%d",&n)!=EOF){

for(i=1;i<=n;i++){
scanf("%d",&num[i]);

mum[i] = num[i];
sum[1][i] = sum[0][i] = 0;
}

qsort(mum, n+1, sizeof(mum[0]), comp);

for(i=1; i<=n; i++){

d = i % 2;
for(j=1; j<=n; j++){

if(mum[i] == num[j])	sum[d][j] = sum[!d][j-1] + 1;
else sum[d][j] = max( sum[!d][j], sum[d][j-1]);

}
}

printf("%d\n",sum[d]
);
}
return 0;
}