leetcode Convert Sorted Array to Binary Search Tree 2.20 难度系数2
2014-01-27 12:48
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Question:
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
Given an array where elements are sorted in ascending order, convert it to a height balanced BST.
/** * Definition for binary tree * public class TreeNode { * int val; * TreeNode left; * TreeNode right; * TreeNode(int x) { val = x; } * } */ public class Solution { public TreeNode sortedArrayToBST(int[] num) { if(num.length==0) return null; if(num.length==1) return new TreeNode(num[0]); int mid = num.length/2; TreeNode root = new TreeNode(num[mid]); int lenleft = mid; int lenright = num.length-mid-1; int[] left = new int[lenleft]; int[] right = new int[lenright]; for(int i=0; i<lenleft; i++) left[i] = num[i]; for(int i=mid+1; i<num.length; i++) right[i-mid-1] = num[i]; root.left = sortedArrayToBST(left); root.right = sortedArrayToBST(right); return root; } }
public class Solution { public TreeNode sortedArrayToBST(int[] num) { if(num.length==0) return null; int mid = num.length/2; TreeNode root = new TreeNode(num[mid]); int leftLen = mid; int rightLen = num.length-mid-1; int[] left = new int[leftLen]; int[] right = new int[rightLen]; System.arraycopy(num,0,left,0,leftLen); System.arraycopy(num,mid+1,right,0,rightLen); root.left = sortedArrayToBST(left); root.right = sortedArrayToBST(right); return root; } }
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